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2 years ago

PLEASE HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

daser333 [38]2 years ago

3 0

Answer:

f(-4) = 5

Step-by-step explanation:

Explanation of

| 5, x < -3

f(x) | 2x² - 4, -3 ≤ x ≤ 4

| 1 - 6x , x > 4

When the x in f(x) is less than -3 than f(x) = 5

When the x in f(x) is greater than -3 but less than 4 then f(x) = 2x² - 4

When the x in f(x) is greater than 4 than f(x) = 1 - 6x

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Now that we know this lets look back at the question.

We want to find f(-4).

Looking at the piece wise function we see that f(-4) follow x < -3 as "x" or -4 is less than -3. When x is less than -3, f(x) = 5, hence f(-4) = 5

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Need help not sure what to do

Rama09 [41]

5a)

2x + 94 = 7x + 49 (vertical angles are equal)

2x - 7x = -94 + 49

-5x = -45

x = 9

Answer

5b)

4y + 7x + 49 = 180 (supplementary angles, sum = 180)

4y + 7(9) + 49 = 180

4y + 112 = 180

4y = 68

y = 17

Answer

x = 6x - 290 (vertical angles are equal)

-5x = -290

x = 58

Answer

7 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

–4r − 10r + –5 = –19

defon

Answer:

r=1

Step-by-step explanation:

-4 r -10r + -5= -19

-4r + (-10r) + -5=-19

-14r+ -5 = -19

-14r + -5 +5= -19+5

-14r= -14

r=1

5 0

3 years ago

Simplify:<br> (2.1 x 10 3) x (2 x 102)

Keith_Richards [23]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Integers between-4 and 2,inclusive

rjkz [21]

The integers between -4 and 2, inclusive would be -4, -3, -2, -1, 0, 1, and 2

3 0

3 years ago