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Semenov [28]
4 years ago
15

Why are epidemics and pandemics a relatively recent phenomenon in human history?

Mathematics
1 answer:
Blizzard [7]4 years ago
7 0
For the greater part of man's opportunity on earth, populaces were little, scattered, and subordinate after chasing and assembling. Those infectious diseases that influenced people were either the consequence of unplanned contamination by zoonoses or lethargic contaminations that maybe had developed with people from their primate precursors. It was just because of the rural upheaval 6,000 to 8,000 years back and the resulting development of inactive populaces sufficiently substantial to help microorganisms particularly subordinate upon human has that epidemics and pandemics seem to have moved toward becoming piece of man's life (Cockburn 1963)
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Which function below is the inverse of f(x)=x^2-36
Artyom0805 [142]

Answer:

+- square root of x+36

Step-by-step explanation:

f(x) = x^2 -36

y = x^2 -36

Exchange x and y

x = y^2 -36

Solve for y

Add 36 to each side

x+36 = y^2 -36+36

x+36 = y^2

Take the square root of each side

±sqrt(x+36) = y

±sqrt(x+36) = f^-1(x)

3 0
3 years ago
9 cos(sin¯¹(x)) = √81 – 81x²
Ira Lisetskai [31]

The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

To answer the question, we need to know what an equation is

<h3>What is an equation?</h3>

An equation is a mathematical expression that show the relationship between two variables.

Given 9cos(sin¯¹(x)) = √(81 – 81x²), we need to show L.H.S = R.H.S

So, L.H.S = 9cos(sin¯¹(x))

= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])

9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]

= √[9² × {1 - sin²(sin¯¹(x)}]

= √[81 × {1 - sin²(sin¯¹(x)}]

= √[81 × {1 - x²}]   (since sin²(sin¯¹(x) = [sin(sin¯¹(x)]² = x²)

= √(81 – 81x²)

= R.H.S

So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

Learn more about equations here:

brainly.com/question/2888445

#SPJ1

6 0
2 years ago
State the number of possible real zeros and turning points of f(x) = x7 – 6x6 + 8x5. Then determine all of the real zeros by fac
Rudiy27

Answer:

steps below

Step-by-step explanation:

f(x) = x⁷ – 6x⁶ + 8x⁵

f'(x) = 7x⁶ - 36x⁵ + 40x⁴

      = x⁴ (7x² - 36x + 40)   ... (1)

Critical point (x,y): x = 0  ,  x = (36 ± √(-36)²-4*7*40) / (2*7) = (18±2√11) / 7

x = 0   or   x = 3.5    or    x = 1.6

plug into (1): y = 0   ,  y = -394.3  ,    y = 10.1

extreme : <u>maximum (1.6 , 10.1)</u>       <u>minimum (3.5 , -394.3)</u>  ... turning points

x⁷ – 6x⁶ + 8x⁵ = x⁵ (x² - 6x + 8) = x⁵ (x-2) (x-4) =0

<u>real zeros: x = 0,   x=2,    x=4</u>

3 0
3 years ago
Write the coordinates of the vertices after a rotation of 180 degrees counterclockwise around the origin.
Umnica [9.8K]

90 degrees you are looking to your side

180 degrees you are looking behind you

around origin of 0,0

the image is flipped into the negative world if it is in posiitve or vice versa

8 0
4 years ago
Hat is the interquartile range of the data represented by the box plot shown below?
marissa [1.9K]

Answer:

Where is the box plot?

Step-by-step explanation:

3 0
4 years ago
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