Answer:
+- square root of x+36
Step-by-step explanation:
f(x) = x^2 -36
y = x^2 -36
Exchange x and y
x = y^2 -36
Solve for y
Add 36 to each side
x+36 = y^2 -36+36
x+36 = y^2
Take the square root of each side
±sqrt(x+36) = y
±sqrt(x+36) = f^-1(x)
The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S
To answer the question, we need to know what an equation is
<h3>What is an equation?</h3>
An equation is a mathematical expression that show the relationship between two variables.
Given 9cos(sin¯¹(x)) = √(81 – 81x²), we need to show L.H.S = R.H.S
So, L.H.S = 9cos(sin¯¹(x))
= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])
9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]
= √[9² × {1 - sin²(sin¯¹(x)}]
= √[81 × {1 - sin²(sin¯¹(x)}]
= √[81 × {1 - x²}] (since sin²(sin¯¹(x) = [sin(sin¯¹(x)]² = x²)
= √(81 – 81x²)
= R.H.S
So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S
Learn more about equations here:
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Answer:
steps below
Step-by-step explanation:
f(x) = x⁷ – 6x⁶ + 8x⁵
f'(x) = 7x⁶ - 36x⁵ + 40x⁴
= x⁴ (7x² - 36x + 40) ... (1)
Critical point (x,y): x = 0 , x = (36 ± √(-36)²-4*7*40) / (2*7) = (18±2√11) / 7
x = 0 or x = 3.5 or x = 1.6
plug into (1): y = 0 , y = -394.3 , y = 10.1
extreme : <u>maximum (1.6 , 10.1)</u> <u>minimum (3.5 , -394.3)</u> ... turning points
x⁷ – 6x⁶ + 8x⁵ = x⁵ (x² - 6x + 8) = x⁵ (x-2) (x-4) =0
<u>real zeros: x = 0, x=2, x=4</u>
90 degrees you are looking to your side
180 degrees you are looking behind you
around origin of 0,0
the image is flipped into the negative world if it is in posiitve or vice versa
Answer:
Where is the box plot?
Step-by-step explanation: