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dezoksy [38]
3 years ago
9

What is 234.506 rounded to the nearest hundredth

Mathematics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

Rounded to the nearest hundredth, 234.506 becomes 234.51.

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5(n+2)=10 how do I solve this
nordsb [41]
Divide both sides by 5 and then n + 2 =2 so the answer is n=0







hope this help
3 0
4 years ago
Please help! 100points! A sequence is defined recursively by the given formulas. Find the first five terms of the sequence.
DiKsa [7]

Answer:

<u>5, 18, 44, 96, 200</u>

Step-by-step explanation:

<u>Given</u>

  • aₙ = 2(aₙ₋₁ + 4)
  • a₁ = 5

<u>First term</u> : 5

<u>Second term</u> : a₂ = 2(a₁ + 4)

  • a₂ = 2(5 + 4) = 2(9) = 18

<u>Third term</u> : a₃ = 2(a₂ + 4) = 2(18 + 4) = 2(22) = 44

<u>Fourth term</u> : a₄ = 2(a₃ + 4) = 2(44 + 4) = 2(48) = 96

<u>Fifth term</u> : a₅ = 2(a₄ + 4) = 2(96 + 4) = 2(100) = 200

Hence, the first 5 terms of the sequence are :

  • <u>5, 18, 44, 96, 200</u>
3 0
3 years ago
Read 2 more answers
The area of a rectangle is 200 square feet. Find its length if its width is 10 feet.
bearhunter [10]

Answer:

20        

Step-by-step explanation:

In area you have to multiply so 10 x ? = 200

10 x 20 = 200

5 0
3 years ago
Trapezoid QRST has two right angles. A 5in. altitude can be drawn dividing QRST into a rectangle and an isosceles right triangle
iVinArrow [24]
The area of the trapezoid is 57.5 square inches.

If you draw out the description, you will see that your trapezoid can be divided into a rectangle that is 9 x 5 and an isosceles right triangle with a base of 5 and height of 5. 

Just find the areas of both and add them together.

Rectangle:
5 x 9 = 45

Triangle:
0.5 x 5 x 5 = 12.5

45 + 12.5 = 57.5
5 0
3 years ago
Jharana got Rs.1881 interest of certain sum for 2year at 9% compounded yearly.find the sum.​
Lana71 [14]

The principal sum is Rs.10,000

Step-by-step explanation:

The formula of compound interest is:

I=P(1+\frac{r}{n})^{nt}-P where:

  • I is the interest
  • P is the principal investment amount (the initial deposit or loan amount)
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

Jharana got Rs.1881 interest of certain sum for 2 year at 9%

compounded yearly

∵ I = Rs.1881

∵ r = (9/100) = 0.09

∵ n = 1 ⇒ compounded yearly

∵ t = 2 years

Substitute all of these values in the rule above

∴ 1881=P(1+\frac{0.09}{1})^{(1)(2)}-P

∴ 1881 = P(1 + 0.09)² - P

∴ 1881 = P(1.09)² - P

∴ 1881 = 1.1881 P - P

∴ 1881 = 0.1881 P

- Divide both sides by 0.1881

∴ P = 10,000

The principal sum is Rs.10,000

Learn more:

You can learn more about the interest in brainly.com/question/11149751

#LearnwithBrainly

3 0
3 years ago
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