7(x-2) +3x=46
7x-14+3x=46
10x-14=46
10x=60
X=6
<span>point (3, 1) and has a slope of –2?
y-1=-2(x-3)</span>
Answer:
{324, 0, -6, 54}
Step-by-step explanation:
Given that F(x) = 3x² − 3 x − 6 If the domain of a the function f(x) is { -10, -1, 1, 5 }.
To get the range, we will find f(x) for all the domains
at x = -10
f(-10) = 3(-10)²-3(-10) - 6
f(-10) = 3(100)-3(-10) - 6
f(-10) = 300+30-6
f(-10) = 330-6
f(-10) = 324
at x = -1
f(-1) = 3(-1)²-3(-1) - 6
f(-1) = 3(1)-3(-1) - 6
f(-1) = 3+3-6
f(-1) = 6-6
f(-1) = 0
at x = 1
f(1) = 3(1)²-3(1) - 6
f(1) = 3(1)-3(1) - 6
f(1) = 3-3-6
f(1) = 0-6
f(1) = -6
at x = 5
f(5) = 3(5)²-3(5) - 6
f(5) = 3(25)-3(5) - 6
f(5) = 75-15-6
f(5) = 60-6
f(5) = 54
Hence the range of the relation are {324, 0, -6, 54}
Hi! i think it’s the last one (270 degrees counterclockwise and 1 unit to the right)
if it was 180 degree, the shape would be in quadrant II, not quadrant III
M = -2 ; parallel slope: m = -2
y = mx +b
2 = -2(2) + b
2 = -4 + b
b = 6
final equation: y = -2x + 6
