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Alexxx [7]
3 years ago
13

I need help if someone would? what is the correlation coefficient of the set of data? round your answer to the nearest thousandt

h
Years: 1, 2, 3, 4, 5, 6, 7, 8
height:2.1, 3.2, 6.8, 7.3, 11.2, 12.6, 13.4, 15.9
Mathematics
1 answer:
RSB [31]3 years ago
8 0
0.98867. there are eight numbers, to get from one number to another use this
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*Absurd answers will be reported* Can the fraction 12/30 be reduced/simplified? If it can, what can it be reduced by?
Fynjy0 [20]

Answer:

divided by 3 12/30 = 4/10 = 2/5

Step-by-step explanation:

4 0
3 years ago
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Mrs.bell has a 256 ounce of soil. What is the greatest number of 6 ounce pots she can completely fill with soil.
Pachacha [2.7K]
42.6, hope that helps!!!
8 0
2 years ago
50 POINTS PLEASE HELP ME
Harrizon [31]

Hello!

f(g(x)) = 4 - <u>2</u><u> </u><u>×</u><u> </u><u>(</u><u>3</u><u>x</u><u>²</u><u>)</u> <=>

<=> f(g(x)) = 4 - 6x²

Answer: B. f(g(x)) = 4 - 6x²

Good luck! :)

5 0
2 years ago
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A recent broadcast of a television show had a 10 ​share, meaning that among 6000 monitored households with TV sets in​ use, 10​%
Kisachek [45]

Answer:

Null and alternative hypothesis

H_0: \pi \geq0.25\\\\H_1: \pi

Test statistic z=-26.82

P-value P=0

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

H_0: \pi \geq0.25\\\\H_1: \pi

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056

The test statistic is calculated as:

z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056}  =-26.82

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

3 0
2 years ago
A sum of money is invested at 12% compounded quarterly. About how long will it take for the amount of money to double?
kompoz [17]

Answer:

  5.9 years

Step-by-step explanation:

We believe a better representation of the compound interest formula is ...

  V(t)=P(1+\dfrac{r}{n})^{nt}

We want to find the value of t for P=1 and V(t)=2. We are told n=4, so the formula becomes ...

  2=(1+\dfrac{.12}{4})^{4t}\\\\\log{(2)}=4t\log{(1.03)}\quad\text{take logs}\\\\t=\dfrac{\log{2}}{4\log{1.03}}\approx\boxed{5.9\quad\text{years}}

8 0
3 years ago
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