Not A C or E So maybe B or D hope this helped a little
23/8 is the answer. Because you do denomiinator times whole. That answer plus numerator
If the question is referring to the least common multiple it is 24
The number of integer values of n for which the value 4000 × (0.4)ⁿ is an integer is; 9
<h3>How to find the integer values in algebra?</h3>
We are given the expression;
4000 × (0.4)ⁿ
This can also be expressed as;
4000 × (²/₅)ⁿ which can further be expressed in exponent form as;
(2⁵ × 5³) × (²/₅)ⁿ = 2⁽⁵ ⁺ ⁿ⁾ × 5⁽³ ⁻ ⁿ⁾
Since this expression is an integer, we need:
1) 5 + n ≥ 0 for which n ≥ -5
2) 3 - n ≥ 0 for which n ≤ 3
Taking the intersection gives;
-5 ≤ n ≤ 3
Thus;
Number of Integer Values = 3 - (-5) + 1 = 9
Read more about Integer Values at; brainly.com/question/17695139
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