Question

Solving a right triangle ‼️ Can someone help me find B, b, and c❓Round to the nearest tenth.

Answer 1

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 given angles from 180 for B

B = 180° - (90 + 39)° = 180° - 129° = 51°

Using the tangent and sine ratios in the right triangle for b and c

tan39° = $\frac{opposite}{adjacent}$ = $\frac{27}{b}$

Multiply both sides by b

b × tan39° = 27 ( divide both sides by tan39° )

b = $\frac{27}{tan39}$ ≈ 7.5 ( to the nearest tenth )

sin39° = $\frac{opposite}{hypotenuse}$ = $\frac{27}{c}$

Multiply both sides by c

c × sin39° = 27 ( divide both sides by sin39° )

c = $\frac{27}{sin39}$ ≈ 28.0 ( to the nearest tenth )