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3 years ago

Please explain step by step

Mathematics

1 answer:

JulijaS [17]3 years ago

6 0

1. Calculate the volume of entire cube as if it was a solid rectangle:
Length x width x height=
20x16x12 = 3,940 cubic inches

2. Calculate the volume of the "missing"
Piece and subtract:
Length x width x height=
20x8x6 = 960 cubic inches
(notice you can find the height of the missing piece by subtracting 12-6)

So your answer is 3,940-960 = 2,980 cubic inches inside the steps

You might be interested in

$0.\overline{5} + 0.19\overline{4}$.

Scilla [17]

Answer:

$0.\overline{5} + 0.19\overline{4}=0.75$

Step-by-step explanation:

Given expression:

$0.\overline{5} + 0.19\overline{4}$

To evaluate the expression.

Solution.

The values are

$0.\overline{5}=0.555555......$

Let $X=0.555555.....$ -----------1

Multiplying 10 both sides.

$10X=5.555555....$ ----------2

Subtracting 1 from 2.

$10X=5.555555....$

- $X=0.555555.....$

-------------------------------------------

$9X=5.0$

Dividing both sides by 9.

$\frac{9X}{9}=\frac{5}{9}$

$X=\frac{5}{9}$

$0.19\overline{4}=0.194444....$

Let $Y=0.1944444..$

Multiplying both sides by 100

$100Y=19.44444..$ ------------3

Multiplying 1000 both sides.

$1000Y=194.4444....$ ----------4

Subtracting 3 from 4.

$1000Y=194.4444....$

- $100Y=19.44444.....$

-------------------------------------------

$900Y=175.0$

Dividing both sides by 900.

$\frac{900Y}{900}=\frac{175}{900}$

$Y=\frac{175}{900}$

So, we can evaluate the given expression as:

⇒ $0.\overline{5} + 0.19\overline{4}$

⇒ $X+Y$

⇒ $\frac{5}{9}+\frac{175}{900}$

Taking LCD = 900

⇒ $\frac{5\times 100}{9\times 100}+\frac{175}{900}$

⇒ $\frac{500}{900}+\frac{175}{900}$

Adding numerators.

⇒ $\frac{500+175}{900}$

⇒ $\frac{675}{900}$

⇒ $0.75$ (Answer)

7 0

3 years ago

Jose's vase can hold up to 2,419 milliliters of water. He poured 1 liter 299 milliliters of water into the empty vase. Then he a

Law Incorporation [45]

The vase will hold 722 milliliters more water

6 0

3 years ago

How do you model a situation in which a function behaves differently over different parts of its domain?

Eduardwww [97]

The situation in which a function behaves differently over different parts of its domain is modeled by considering it to be a piecewise function.

Such a situation can be explained through an example:

f(x)= { 2x, for x > 0

{ 1, for x = 0

{ -2x, for x < 0

now, when we take x value less than 0, say x= -1

thus, f(x)= f(-1)= -2(-1) = 2 , here we used f(x) given x<0

now, when we take x value more than 0, say x= 2

thus, f(x)= f(1)= 2(1) = 2, here we used f(x) given x>0

now, when we take x = 0,

thus, f(x)= f(0)= 1, here we used f(x) given x=0

this is how we model picewise function, we use f(x) as per the value of x. Following image shows plotted answer for this example.

Since inequalities given are exclusive of 0, we leave the dot at the origin unfilled. Now, for x = 0. Since the value is constant at f(x) =1, we plotted a point at (0,1)

more questions on picewise functions brainly.com/question/12089993

#SPJ4

5 0

1 year ago

The figure shown below is composed of a semicircle and a non-overlapping equilateral triangle and contains a hole that is also c

Sloan [31]

Check the picture below.

since we know the radius of the larger semicircle is 8, thus its diameter is 16, which is the length of one side of the equilateral triangle. We also know the smaller semicircle has a radius of 1/3, and thus a diameter of 2/3, namely the lenght of one side of the small equilateral triangle.

now, if we just can get the area of the larger figure and the area of the smaller one and subtract the smaller from the larger, we'll be in effect making a hole/gap in the larger and what's leftover is the shaded figure.

$\bf \stackrel{\textit{area of a semi-circle}}{A=\cfrac{1}{2}\pi r^2\qquad r=radius}~\hspace{10em}\stackrel{\textit{area of an equilateral triangle}}{A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\stackrel{side's}{length}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\left[ \stackrel{\textit{larger figure}}{\cfrac{1}{2}\pi 8^2~~+~~\cfrac{16^2\sqrt{3}}{4}} \right]\qquad -\qquad \left[ \cfrac{1}{2}\pi \left( \cfrac{1}{3} \right)^2 +\cfrac{\left( \frac{2}{3} \right)^2\sqrt{3}}{4}\right]}$

$\bf \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\frac{4}{9}\sqrt{3}}{4} \right] \\\\\\ \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\sqrt{3}}{9} \right]~~\approx~~ 211.38 - 0.37~~\approx~~ 211.01$

3 0

4 years ago

The perimeter of a square is80-64y units. Which expression can be used to show the side length of one side of the square?

erik [133]

(80-64y)/4
.........

8 0

3 years ago

Please explain step by step​

Please explain step by step