I NEED YOUR HELP!!!!

umka21 [38]

Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.

Answer:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

Step-by-step explanation:

Given the expression

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)$

solving the expression

$=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)$

apply the rule: $a^0=1,\:a\ne \:0$

$=-7+5x^2-x+6-\left(-8x^2+x+3\right)$

$=-7+5x^2-x+6+8x^2-x-3$

simplify

$=13x^2-2x-4$

Therefore, the simplified form is:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.

8 0

3 years ago

Complete the statement about parallelogram ABCD.

Crank

Step-by-step explanation:

Opposite angles of parallelograms are congruent

4 0

3 years ago

X Find the value of x. Show 3 10 your work.

pickupchik [31]

Step-by-step explanation:

Hello, there!!!

Let ABC be a Right angled triangle, 

where, AB = 3

BC= 10

and AC= x

now,

As the triangle is a Right angled triangle, taking angle C asrefrence angle. we get,

 h= AC = x

p= AB = 3

b= BC= 10

now, by Pythagoras relation we get, 

 $h = \sqrt{ {p}^{2} + {b}^{2} }$ 

 $or ,\: h = \sqrt{ {3}^{2} + {10}^{2} }$ 

by simplifying it we get, 

h = 10.44030

Therefore, the answer is x= 10.

Hope it helps...

7 0

3 years ago

The base of a triangle is 6centimeter 50 millimeter

NARA [144]

Red Given:

Length of base is "6cm50mm"
length of base= 11cm
Height is "400mm"
height= 40 cm

Red Solution:

Area of triangle =1/2bh
ar.(triangle)=1/2(11cm)(40cm)
ar.(triangle)=(11cm)(20 cm)

Orange ar.(Triangle)=220cm^2

7 0

3 years ago

Read 2 more answers

What is the sum of the infinite geometric series with a1=42 and r=6/5?

Cerrena [4.2K]

This infinite sum is given by

a
S = ------ but ONLY if r<1. Here, r>1, so the infinite sum does not exist.
1-r

8 0

3 years ago