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2 years ago

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I NEED YOUR HELP!!!!

1 answer:

Alex17521 [72]2 years ago

5 0

Its the last one as i remember

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Challenge A large university accepts 40% of the students who apply. Of the students the un

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100,000

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Answer:you need use a scale and the numbers that are provided of the dimensions of the room

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2 years ago

In the Pi Corporation, 4/5 of the managers are female. If there are 64 female managers, how many managers in total are there? Ho

oksano4ka [1.4K]

Step-by-step explanation:

$\frac{4}{5} = 64 \\ \frac{1}{5} = 64 \div 4 \\ \: \: \: \: \: \: = 16 \\ total \: managers \: = 16 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 80 \\ number \: of \: male \: \: managers \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{5}{5} - \frac{4}{5} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{5} = 16$

<em>hop</em><em>e</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

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2 years ago

HELP ME PLZ SO VERY PLZ PLZ

yaroslaw [1]

The value of x will be 23

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2 years ago

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Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

2 years ago