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Nadya [2.5K]
3 years ago
15

Rolling a fair​ six-sided die is supposed to randomly generate the numbers 1 through 6. Explain what random means in this contex

t? Choose the correct answer below.
a. That if a 1 is rolled it that means that each other number was not rolled.
b. That the only possible outcomes are​ 1, 2,​ 3, 4,​ 5, and 6.
c. That each result will not be influenced by the previous result of the die roll.
d. That in the long​ run, a fair die will produce roughly equal amounts of the numbers 1 through 6 when rolled. But for each roll each value 1 through 6 is equally likely.
Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer: D.

Step-by-step explanation: It explains the definition of random in particular with the die.

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How do I solve part b and c
OLEGan [10]

Answer:

part a: 52%

part b: 0.4

part c: 0.24

Step-by-step explanation:

For part one, you find the frequency of the number of people that are less that 20. You add the number of tics in each bar and you divide by the total.

so for part a it is (7+6+9+4)/ (7+6+9+4+4+12+8)

for part b you add up the values that are greater than 25(less than 35)

(12+8)/total

part c you find the number of people between 25 and 30

that's 12

over total

12/total

4 0
3 years ago
Given the function f(x) = 3x + 1 what is f(-2)?
Readme [11.4K]

Answer:

-5

Step-by-step explanation:

f(-2) means that -2 is going to be our input in this function.

To solve this, simply substitute -2 for x in the expression given.

If f(x) = 3x+1, then f(-2) = 3(-2) + 1

3(-2)+1 = -6+1 = -5

Hope this helped!

7 0
2 years ago
Read 2 more answers
2/x multiplied by what equals 1
Varvara68 [4.7K]

Answer:

Multiplied by2x

2/x ×2x =1

5 0
3 years ago
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
4y and 5xy are like terms or are unlike terms
Norma-Jean [14]

Answer:

Unlike terms

Step-by-step explanation:

If it was 4y and 5y it would be like. Adding the x though makes them unlike terms, you cannot combine them

4 0
3 years ago
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