7 × (-3) ×(-2)2 =
7 × -3 × -4 = (you have to eliminate all parenthesis in the equation.)
7 × -12 = -84
so your answer would be: C
Answer:
3/10
Step-by-step explanation:
9-6=3
both fractions have the same denominator so they keep it
9/10 - 6/10 = 3/10
<h3>3/10 is also 0.33</h3>
Is it just me or is it just that I can't see anything
I'm going to assume the 4 and 3 are exponents and the expression is
.
The first step is to separate the coefficients of 3 and -6 from the variables and to multiply those as normal:

As for the variables, you want to recognize that
means
and
means
, so

In total, there are 7 a's being multiplied, so

Putting this all together, we have:

1)

where m is the slope
We know the slope is 5 and the line passes through the point (4,3).

The equation of the line is:

Now the second point:

The answer:
The value of y is -7.
2)
The line passes through the origin, or the point (0,0), and has a slope of -32.
The slope is negative so the line goes down from left to right.
It crosses both x and y axes in the point (0,0).
Therefore, it only passes through II and IV quadrant.
You can also find the equation of the line, find one more point and draw it.

Find the y-coordinate of the point for example (1,y).

The line passes through the points (0,0) and (1,-32). Now you can draw it (see the attachment).
The answer:
The line passes through quadrants II and IV.