Let after t hours the distances D1<span> traveled by car A</span>
=> D1<span> = 30 t</span>
Car B starts at 10 am and will, therefore, have spent one hour less than car A when it passes it.
After (t - 1) hours, distance D2<span> traveled by car B </span>
=> D2<span> = 40 (t - 1)</span>
When car B passes car A, they are at the same distance from the starting point and therefore<span> D1 = D2 </span>
=> 30 t = 40 (t - 1)
Solve the equation for t,
=> 30 t = 40t - 40
=> 10 t = 40
=> t = 4
=><span> Car B passes car A at = 9 + 4 = 13 pm.</span>
Answer:
<u>Option a. √35/6</u>
Step-by-step explanation:
Given sin θ = -1/6 and tan θ = -√35/35
We should know that :
tan θ = (sin θ)/(cos θ)
∴ Cos θ = (sin θ)/(tan θ)
∴ Cos θ = (-1/6)/(-√35/35) = (-1/6) * (-35/√35)
= 35/(6√35) = (√35 * √35)/(6√35) = √35/6
<u>The answer is option a. √35/6</u>
43.= \frac{2x}{5x^2+ 12x{} -13}
[/tex]
Since there's two of each type of number, and the total number of tiles is 8, you would get 2/8 for any event to occur. Simplify 2/8 to get 1/4.
Answer:
x = -27
Step-by-step explanation:
