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4 years ago

Can someone please explain how to solve these two math equations?

1 answer:

4 0

#1.

Question: 2x^2 − 3x − 35 = 0

Step 1: Factor left side of equation): (2x + 7) (x − 5) = 0
Step 2: Set factors equal to 0.): 2x + 7 = 0 or x − 5 = 0

ANSWER: x = −7/2 or x = 5
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#2.

Question: 56z^2 + 2 = 22z

Step 1: Subtract 22z from both sides.):

56z^2 + 2 −22z = 22z − 22z
56z^2 − 22z + 2 = 0
Step 2: Factor left side of equation.):


2(7z − 1)(4z − 1) = 0

Step 3: Set factors equal to 0.):


7z − 1 = 0 or 4z − 1 = 0

ANSWER: z = 1/7 or z = 1/4

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4 years ago

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Movies Tonight is a typical video and DVD movie rental outlet for home-viewing customers. During the weeknight evenings, custome

stepladder [879]

Answer:

the probability having no customers are in the system is 0.375

Step-by-step explanation:

The computation of the probability having no customers are in the system is as follows;

Given that the arrival rate is 1.25 customers per minute

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Based on the above information, the probability is

$=P_0\\\\=(1-\frac{\lambda }{\mu })\\\\=(1-\frac{1.25}{2})\\\\=1-0.625\\\\= 0.375$

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6 0

3 years ago

100 POINTS HELP ASAP Linear Combination

notka56 [123]

Answer:

1) $x=\dfrac12$

2) $n = -3 \ \ \textsf{and} \ \ m = -4$

3) see below

4) A: 0 = 1

Step-by-step explanation:

Question 1

$15-0.5(4x-2)+4x=17$

$\implies 15-2x+1+4x=17$

$\implies 2x+16=17$

$\implies 2x=1$

$\implies x=\dfrac12$

Question 2

$\textsf{rearrange} \ n=m+1 :$

$\implies -m=-n+1$

$\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\$

$\implies0=n+3$

$\implies n=-3$

$\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:$

$\implies m=-3-1$

$\implies m=-4$

Question 3

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

Question 4

$3j=k$

$k=3j+1$

$\textsf{rearrange} \ 3j=k :$

$\implies -k=-3j$

$\textsf{add equations}\ -k=-3j \ \ \textsf{and}\ \ k=3j+1:$

$\implies 0=1$

Solution = A

6 0

3 years ago

When 2x^2 - 20x + 49 = 19 is written in the form (x - p)^2 = q, what is the value of q? Show your work please.

Strike441 [17]

= 2x^2 - 20x + 49 = 2(x^2 - 10x + 49/2)

y= 2((x-5)^2 - 25 + 49/2) = 2((x-5)^2 - 1/2) = 2(x-5)^2 - 1

q =5, r=-1, p=2

Vertex = (q,r) = (5,-1)

hope it helps plz mark as brainliest

5 0

4 years ago

I need to turn this in in 2 hours please hurry

Nuetrik [128]

Answer:

2) 162°, 72°, 108°

3) 144°, 54°, 126°

Step-by-step explanation:

1) Multiply the equation by 2sin(θ) to get an equation that looks like ...

sin(θ) = <some numerical expression>

Use your knowledge of the sines of special angles to find two angles that have this sine value. (The attached table along with the relations discussed below will get you there.)

____

2, 3) You need to review the meaning of "supplement".

It is true that ...

sin(θ) = sin(θ+360°),

but it is also true that ...

sin(θ) = sin(180°-θ) . . . . the supplement of the angle

This latter relation is the one applicable to this question.

Similarly, it is true that ...

cos(θ) = -cos(θ+180°),

but it is also true that ...

cos(θ) = -cos(180°-θ) . . . . the supplement of the angle

As above, it is this latter relation that applies to problems 2 and 3.

6 0

3 years ago