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Pachacha [2.7K]
3 years ago
10

Problem Osvoldo has a goal of getting at least 30% of his grams of carbohydrates each day from whole grains. Today, he ate 220 g

rams of carbohydrates, and 55 grams were from whole grains. Did Osvoldo meet his goal? Why?
Mathematics
2 answers:
tekilochka [14]3 years ago
5 0

No.

30% of 220 is 66 and 55 is less than 66

KonstantinChe [14]3 years ago
5 0

Answer:

Osvoldo did not meet his goal.

Step-by-step explanation:

It is given that Osvoldo has a goal of getting at least 30% of his grams of carbohydrates each day from whole grains.

Today, he ate = 220 grams of carbohydrates

Carbohydrate from whole grains = 55 grams

We need to check whether Osvoldo meet his goal or not.

We have to check whether 55 is at least 30% of 220 or not.

\dfrac{55}{220}\times 100=25\%

Since 55 is 25% of 220, therefore he gets only 25% of his grams of carbohydrates each day from whole grains.

Hence, Osvoldo did not meet his goal.

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Give the equation for a circle with the given center and radius.Center at (-10, -4), radius = 5A. (x−10)^2+(y−4)^2=25B. (x−4)^2+
BaLLatris [955]

D)(x+10)^2+(y+4)^2=5^2=25

Explanation

Step 1

We know that the general equation for a circle is

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\  \end{gathered}

where

(h,k) is the center of the circel

and r is the radius

then, all we need to do is replace

Let

\begin{gathered} \text{center}\Rightarrow(h,k)\Rightarrow(-10,-4) \\ \text{radius}\Rightarrow r\Rightarrow5 \end{gathered}

replace the values

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-(-10))^2+(y-(-4))^2=5^2 \\ (x+10)^2+(y+4)^2=5^2=25 \end{gathered}

therefore, the answer is

D)(x+10)^2+(y+4)^2=5^2=25

I hope this helps you

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2 years ago
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kow [346]
Correct answer:
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3 years ago
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Leya [2.2K]

Answer:

B) 2.25

Step-by-step explanation:

Given:

x = -2

y = 4

z = -5

Work:

\frac{x^2-z}{y} \\\\\frac{(-2)^2-(-5)}{4}\\\\\frac{4+5}{4} \\\\\frac{9}{4} \\\\2.25

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3 years ago
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asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
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-------------------------------

\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
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\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
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