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Nat2105 [25]
3 years ago
7

What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num

ber of real solutions the equation has?
Mathematics
2 answers:
forsale [732]3 years ago
3 0
(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
-4

The discriminant is negative so there are no real number solutions.
Nutka1998 [239]3 years ago
3 0

Answer:

<em>The discriminant is -4 so there is no real number solutions</em>

Step-by-step explanation:

100% edu

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Place the following objects in order from greatest to least gravitational force. Explain your answer.
kozerog [31]

well when thinking of gravity you have to think of the size and mass of the object so,

The sun (largest and most mass)

Earth

Earth's moon

Discover satellite (cause it's tiny and light compared to the sun!)

7 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
3 years ago
4 questions! Write an equation in slope-intercept form for each of the following:
AysviL [449]
1) y= -4x+c

2) y= 3x+c replace x and y to find c , 5=3(2)+c
C= -1
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3) find slope first m=y2-y1/x2-x1 = 0-(-1)/-2-1 = 1/-3 and now you have y= -1/3x+c to find c just replace any of the given points , 0= -1/3(-2)+c
C= -2/3 and so y= -1/3x-2/3

4) DO THE SAME STEP AS NUMBER 3 and enjoy!
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2 years ago
Factor the following expression using the GCF.
Jet001 [13]

Answer:

the answer to your question is 8r(d-3)

hope this helps :-)

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What is more accurate, mean or average? Explain why.
Airida [17]
It can be viewed different to what is more accurate depending on the relation of this question to another.
3 0
3 years ago
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