The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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the marked angles are complementary → B
All 3 triangles are right with one angle = 90°
the sum of the angles in a triangle = 180°
thus the remaining 2 marked angles sum to 90°, thus are complementary
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Answer:
p=p+25%p
Step-by-step explanation:
hope this was helpful
pls mark Brainliest
so that i can
rank up ;p
its not worth 25 points but ok here u go let's solve your equation step-by-step.
3y−1=13−4y
Step 1: Simplify both sides of the equation.
3y−1=13−4y
3y+−1=13+−4y
3y−1=−4y+13
Step 2: Add 4y to both sides.
3y−1+4y=−4y+13+4y
7y−1=13
Step 3: Add 1 to both sides.
7y−1+1=13+1
7y=14
Step 4: Divide both sides by 7.
7y
7
=
14
7
y=2
Answer:
y=2 so there your answer is this equation has one solution your welcome
