the area A of the cross section of the column is
.
<u>Step-by-step explanation:</u>
Here we have , building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18π, pi meters. We need to find What is the area A of the cross section of the column .Let's find out:
We know that , Circumference of circle = 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
We know that area of circle = 
⇒ 
⇒ 
⇒ 
Therefore , the area A of the cross section of the column is
.
Part A
5x - 5 >= 10 or-3x + 1 > 13
1) This is a disjunction (OR)
5x - 5 >= 10
5x >= 15
x >= 3
or
-3x + 1 > 13
-3x > 12
x < -4
Answer
x <- 4 or x >= 3
Part C:
1) This is a conjunction (And)
5x+ 3 <= 18 and 4 - x < 6
5x <= 15 and - x < 2
x <= 3 and x > -2
Answer
-2 < x <= 3
PerSolve.
After filling a gas tank the odometer read
39 comma 007.239,007.2.
After the next filling it read
39 comma 469.239,469.2.
It took
16.516.5
gal to fill the tank. How many miles per gallon did the driver get?
Answer:
6720ft^3
Step-by-step explanation:
37²-12² = a²
1225 = a²
√1225 = a
a = 35
35(24²/3) =
35(576/3) =
35•192 = 6720 cm³
Answer:
Part A: b < 28
Part D: n < 56
Step-by-step explanation:
part A: divide each term in and simplify.
Inequality Form: b < 28
part d: this is already solved but can be shown in multiple forms.
Inequality Form: n < 56
Interval Notation: (
-∞
, 56)