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maks197457 [2]
4 years ago
9

Which expression is equivalent to 10^2 • 10^4

Mathematics
2 answers:
kolezko [41]4 years ago
7 0

Answer:

10^6

Step-by-step explanation:

(10^2)(10^4)

=10^2*10^4

=(10*10)*(10*10*10*10)

=10*10*10*10*10*10

=10^6

gayaneshka [121]4 years ago
5 0
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ When you multiply, you add the powers

Therefore, the answer is C. 10^{6}

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Find the coordinates of Cif B(5,-4) is the midpoint of AC and A has coordinates of (7,3).
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The cost of breakfast cereal is Rs for 1 kg Calculate how much 25<br>breakfast cereal will cost.​
Irina-Kira [14]

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25 gram = 1000\35 rs

Step-by-step explanation:

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3 years ago
What is the median of the following data set?<br> (3, 4, 2, 8, 5)<br> 02<br> 03<br> 04<br> 06
serious [3.7K]

Answer:

4

Step-by-step explanation:

The median is the middle number when the list is sorted from least to greatest or greatest to least.

We make this list to get 2,3,4,5,8 or 8,5,4,3,2 and the middle number in both lists is 4.

7 0
2 years ago
Find the radius of convergence R, then determine the interval of convergence
Hunter-Best [27]

The radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series. This can be obtained by using ratio test.  

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

\lim_{n \to \infty}  | \frac{a_{n+1} }{a_{n} } | = β

  • If β < 1, then the series converges
  • If β > 1, then the series diverges
  • If β = 1, then the series inconclusive

Here aₙ = (n²/n!) xⁿ⁺³  and  aₙ₊₁ = ((n+1)²/(n+1)!) xⁿ⁺¹⁺³ = ((n+1)²/(n+1)!) xⁿ⁺⁴

Now limit is taken,

\lim_{n \to \infty}  | \frac{a_{n+1} }{a_{n} } | = \lim_{n \to \infty}  | \frac{((n+1)^{2} /(n+1)!) x^{n+4}  }{(n^{2} /n!) x^{n+3}  } |

                      = \lim_{n \to \infty}  | \frac{((n+1)^{2} ) n!x^{n+4}  }{(n+1)!(n^{2} ) x^{n+3}  } |

                      = \lim_{n \to \infty}  | \frac{((1+1/n)^{2} ) x  }{(n+1)} |  

                      =   \lim_{n \to \infty}  | \frac{ x  }{(n+1)} |  = 0 < 1

Since the limit is less than 1 the series is converging.

We get that,

interval of convergence = (-∞, ∞)

radius of convergence R = ∞

Hence the radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series.

Learn more about power series here:

brainly.com/question/18763238

#SPJ1

6 0
1 year ago
Read 2 more answers
What is the average?<br> 3458
Rina8888 [55]
Im guessing you meant whats the average of 3,4,5, and 8. which would be 5.

Add 3,4,5, and 8 and then divide by how many number you added up which would be 4.
4 0
3 years ago
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