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2 years ago

Select all the descriptions that apply to the transformation.

Mathematics

2 answers:

Dafna1 [17]2 years ago

7 0

Answer:

Step-by-step explanation:

brilliants [131]2 years ago

7 0

D hope it’s correct!!!!!!!!!!!!!

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A six sided number cube is rolled twice what is the probability that the first roll is an even number and the second roll is a n

sp2606 [1]

Answer:

50% of rolling an even number.

33.33% of rolling a number greater than 4.

Step-by-step explanation:

<h2><em>Even Number Probability: </em></h2>

There're three possibilities to roll an even number: 2, 4, and 6. If it's a six sided dice, there're a total of six rolling possibilities, so the ratio is 3:6, 1:2, or 50% chance of rolling an even number.

<h2><em>Greater Than Four Probability:</em></h2>

There're only two number greater than four on a traditional six sided dice: 5 and 6. There're, again, six sides on a six sided dice, so the ratio of rolling a number greater than four is 2:6, 1:3, or 33.33%.

4 0

3 years ago

Read 2 more answers

What is the mean of the data set? <br><br>{50 54 62 48 49 52}

Fynjy0 [20]

To find the mean of a data set, you have to add all of the numbers and divide by the number of data.
So
50 + 54 + 62 + 48 + 49 + 52
To get 315.
315 divided by 6 is 52.5
So the mean of he data set is 52.5
Hope this helps :)

5 0

3 years ago

Read 2 more answers

Jake has a bag of 50 beads, some of which are blue and the remaining are green. Jake randomly pulls out a bead from the bag, rec

noname [10]

Answer:

The answer is 40 because you have a ratio of 4:1 (16:4). If you multiply by ten, it becomes 40:10.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How many integers between 10 and 60, inclusive, can be evenly divided by neither 2 nor 3?

erastovalidia [21]

Find total number of integers.

$a_1=10,a_n=60,d=1 \\a_n=a_1+(n-1)d \\60=10+(n-1)1 \\n-1=50 \\n=51$

Find how many integers is divisible by 2.

$a_1=10,a_n=60,d=2
\\a_n=a_1+(n-1)d
\\60=10+(n-1)2
\\2(n-1)=50
\\n-1=25
\\n=26$

Eliminate even numbers.

11, 13, 15,..., 57, 59

This array contains 51 - 26 = 25 numbers.

Eliminate numbers before the first number divisible by 3 and after the last number divisible by 3.

15, 17, 19,..., 55, 57

This array contains 25 - 3 = 22 numbers.

Now we should eliminate numbers divisible by 3: 15, 21, 27...

$a_1=15,a_n=57,d=6,n=?
\\a_n=a_1+(n-1)d
\\57=15+(n-1)6
\\6(n-1)=42
\\n-1=7
\\n=8$

There are 8 such numbers.

Therefore, there are 25 - 8 = 17 numbers that <span>can be evenly divided by neither 2 nor 3</span>

6 0

3 years ago

Use this picture to solve for X

Zepler [3.9K]

Answer:

x=2

Step-by-step explanation:

i would set up a system of equation using the pythagorean theorem:

1^2+x^2=z^2

4^2+x^2=y^2

Add up these equations to get:

17+2x^2=y^2+z^2

But notice that

y^2+z^2=5^2

So you can substitute

17+2x^2=25

2x^2=8

x^2=4

x=2

8 0

2 years ago