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3 years ago

Solve: 89-4h=57-4h Thanks

2 answers:

6 0

89-4h=57-4h
89-4h-57=57-57-4h (subtracted 57 from both sides)
32-4h=-4h
32-4h+4h=-4h+4h (added 4h to both sides)
32=0
There are no sulutions unless you have a value but this is a simplified version: 32=0

Keith_Richards [23]3 years ago

5 0

89-4h=57-4h
89<span>≠57

that equation has no solution, 89 cannot equal 57</span>

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Write the equation of the line in slope-intercept form passing through the points (-4,2) and (1,12)

alexira [117]

Answer:

y = 2x + 10

Step-by-step explanation:

Find the slope:

12 - 2 / 1 - (-4)

10 / 5 = 2

Write in point-slope form:

y - 12 = 2(x - 1)

rearrange:

y - 12 = 2x - 2

y = 2x + 10

6 0

3 years ago

PLEASE HELP

vova2212 [387]

5 x 5/2 = 25/2

answer
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8 0

3 years ago

Read 2 more answers

Please help fast! give me the equation

uranmaximum [27]

$\begin{bmatrix}x=\frac{\pi }{2}+2\pi n\\ x=\frac{3\pi }{2}+2\pi n\\ x=\frac{3\pi }{4}+\pi n\\ x=\frac{7\pi }{4}+\pi n\end{bmatrix}$

$\begin{bmatrix}\frac{3\pi }{2}+2\pi n=\frac{\pi }{2}+2\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{3\pi }{4}+\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{7\pi }{4}+\pi n\end{bmatrix}$

$\pi =0$

- hope this helps! -

6 0

3 years ago

Each of the 6 cats in a pet store was weighed. what is the mean and median weights of these cats. 9, 8, 14, 12, 5

tresset_1 [31]

Mean= 9+8+14+12+5+14 divided by 6
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3 0

3 years ago

If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.

harina [27]

Answer:

Step-by-step explanation:

When we simplify we get $z(6xy+21x+2y+7)+30xy+105x+10y=812.$

Then we continue to factor to get: $(z+5)(6xy+21x+2y+7)&=847.$

We then see that we can factor $(6xy+21x+2y+7)$ into $(z+5)(3x+1)(2y+7)&=847.$

we then do the prime factorization of 847, which i think is, $7*11*11$ . we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0

4 years ago