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3 years ago

What is the value of m? O 10 O 30 O 70 O 150

Mathematics

1 answer:

MAXImum [283]3 years ago

5 0

30is the correct answer

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The difference between 7 and -15 the translation is

liraira [26]

Answer:

Step-by-step explanation:

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3 years ago

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What is the answer I need help

KATRIN_1 [288]

I know what the answer is

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2 years ago

Write the equation of a line that is perpendicular to y=-4/3x+9 and goes through (8,-5). Do not use spaces in your answer. Enter

liq [111]

Answer:

y=3/4x-11

Step-by-step explanation:

When a line is perpendicular to another line, their slope is the opposite reciprocal of that. So in this case, the slope of the perpendicular line would be positive 3/4. Next, plug in the points (8,-5) in the y=mx+b formula along with the new slope. In conclusion, the new point slope formula is y=3/4x-11.

Hope this helps! :)

8 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

Simplify the expression. 16 x 4 -4

Lorico [155]

Answer:

The answer is 60

Step-by-step explanation:

16 x 4 - 4

64 - 4

Hope this helped!

7 0

2 years ago