Step-by-step explanation:
Claim:
it takes n - 1 number of breaks to break the bar into n separate squares for all integers n.
Basic case -> n = 1
The bar is already completely broken into pieces.
Case -> n ≥ 2
Assuming that assertion is true for all rectangular bars with fewer than n squares. Break the bar into two pieces of size k and n - k where 1 ≤ k < n
The bar with k squares requires k − 1 breaks and the bar with n − k squares
requires n − k − 1 breaks.
So the original bar requires 1 + (k−1) + (n−k−1) breaks.
simplifying yields,
1 + k − 1 + n − k − 1
1 - 1 + n - 1
n - 1
Therefore, we proved as we claimed that it takes n - 1 breaks to break the bar into n separate squares.
Answer:
the answer is b
Step-by-step explanation:
i took the test it is b. The sum of the areas of faces A, B, and C.
She wants 25she divides each by 12 to get for 1 person then multiplies by 25 to get for 25 peoplemulitply each ingredient by 25/12
for multiplying fractions, try to put them in standard a/b form first
flour1 and 1/2 times 25/12=2/2+1/2 times 25/12=3/2 times 25/12=75/24=25/8=24/8+1/8=3+1/8=3 and 1/8 cup flour
baking powder1 times 25/12=25/12=24/12+1/12=2+1/12=2 and 1/12 tsp baking powder
salt1/2 times 25/12=25/24=24/24+1/24=1+1/24=1 and 1/24 tsp salt
butter1 times 25/12=25/12=24/12+1/12=2+1/12=2 and 1/12 stick of butter
sugar
1 times 25/12=25/12=24/12+1/12=2+1/12=2 and 1/12 cup of sugar
eggs3 times 25/12=3/1 times 25/12=75/12=25/4=24/4+1/4=6+1/4=6 and 1/4 eggs
vanilla extract
1 and 1/2 times 25/12=2/2+1/2 times 25/12=3/2 times 25/12=75/24=25/8=24/8+1/8=3+1/8=3 and 1/8 tsp vainlla extract
milk3/4 times 25/12=75/48=25/16=16/16+9/16=1+9/16=1 and 9/16 cup milk
for 25 servings
she needs
3 and 1/8 cup flour
2 and 1/12 tsp baking powder1 and 1/24 tsp salt2 and 1/12 stick of butter2 and 1/12 cup of sugar
6 and 1/4 eggs3 and 1/8 tsp vanilla extract1 and 9/16 cup milk
Answer:
- The Range is the set of all outputs for a function
- The Domain is the set of all inputs for a function
For example
Here Domain and range both are set of all real numbers
