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3 years ago

You spin the spinner and flip a coin. Find the probability of the compound event.

Mathematics

1 answer:

zimovet [89]3 years ago

4 0

Answer:

the compound probability is 1/8.

Step-by-step explanation:

1/4 for the spinner x 1/2 for the coin

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Answer:

Step-by-step explanation:

1st step: 36/9 = 4

54 - 4 + 14 (since all operations are addition and subtraction, just work left to right)

50 + 14 = 64

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goblinko [34]

10 is a factor of 20

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3 years ago

PLEASE HELP

bezimeni [28]

Answer:

B. 6.2

Step-by-step explanation:

The calculation is done by hand and verified by a TI-84 calculator.

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If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

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2 years ago

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The answer for this is A

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