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Setler79 [48]
2 years ago
6

When installing a SATA hard drive, is it true or false that you need to move the jumpers on the back of the drive to instruct th

e computer on which hard drive is the bootable drive?
Computers and Technology
1 answer:
antiseptic1488 [7]2 years ago
7 0

Answer:

This is false.

Explanation:

SATA drives do not have jumpers, because they don't use the master/slave feature. They are connected to the motherboard, and they are ready to work.

The master/slave feature was used by IDE hard drives.15 years ago, most motherboards didn't have too many IDE slots to place more than 1 or 2 HDDs, the IDE cable allowed you to connect 2 drives to 1 cable, greatly increasing your computer's storage space.

It was recommended to set as master the drive connected directly to the motherboard, and the other one as slave.

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Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
leonid [27]

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = \mathbf{\bigg ( ( 42 -  (no. \ of \  failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \  comparisons) ) \bigg ) }

Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )

Total number of character comparison = 41 + 2

Total number of character comparison = 43

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