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Artist 52 [7]
3 years ago
9

Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMile

s. Sample output for the given program:
Min miles: -10
Max miles: 40
Here's what I have so far:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int NUM_ROWS = 2;
final int NUM_COLS = 2;
int [][] milesTracker = new int[NUM_ROWS][NUM_COLS];
int i = 0;
int j = 0;
int maxMiles = 0; // Assign with first element in milesTracker before loop
int minMiles = 0; // Assign with first element in milesTracker before loop
milesTracker[0][0] = -10;
milesTracker[0][1] = 20;
milesTracker[1][0] = 30;
milesTracker[1][1] = 40;
//edit from here
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] > maxMiles){
maxMiles = milesTracker[i][j];
}
}
}
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] < minMiles){
minMiles = milesTracker[i][j];
}
}
}
//edit to here
System.out.println("Min miles: " + minMiles);
System.out.println("Max miles: " + maxMiles);
}
Computers and Technology
1 answer:
lina2011 [118]3 years ago
8 0

Answer: 40, 4

Explanation:

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Answer:

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Explanation:

The program works as follows:

The function sumSquares(num) that takes an integer num as parameter and returns the sum of squares of numbers from 1 to num

The first if condition checks if value of num is positive. If this condition evaluates to true then the another if statement inside this if statement is executed which checks if the value of num is 0. If this condition evaluates to true then the program returns 0. However if this condition evaluates to false then the else part executes which has the following statement:

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sumSquare() method is called again and the value 0 is passed as num

As the value of num=0 So the if (num == 0):  condition evaluates to true and the statement returns 0 executes which returns 0:

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Hence the output is:

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The screenshot of the program along with its output is attached.

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