Answer:
3^x=9^{x+5}
Step-by-step explanation:
3^x=9^{x+5}
x^2-x-6=0
x^4-5x^2+4=0
\sqrt{x-1}-x=-7
\left|3x+1\right|=4
\log _2\left(x+1\right)=\log _3\left(27\right)
3^x=9^{x+5}
If request to solve;
\mathrm{Convert\:}9^{x+5}\mathrm{\:to\:base\:}3
9^{x+5}=\left(3^2\right)^{x+5}
\mathrm{Solve\:}\:x=2\left(x+5\right):\quad x=-10
{ 5+ pi}/ 6{ 2n/22/7} ( 5, pi /6 2n 3.147 }
I think the answer to this question is b
Answer:
It is not proportional
Step-by-step explanation:
To figure out if something is proportional they have to equal the same thing.
As you can see on the problem 0.2 and 0.2 are the same thing, and since one is on the numerator and one is on the demoninator those two can cross out.
Now we come to the 0.08 and the 0.8.
They are not the same thing the 0.08 has an extra 0.
So this is not proportional
<em>-I hope this helps! -Karen</em>
