<span>(4 · 2^5) ÷ (2^3 · 1/16 )
</span>= (2^2 · 2^5) ÷ (2^3 · 2^-4 )
= (2^7) ÷ (2^-1)
= 2^8
Answer:
Step-by-step explanation:
common difference d=3-1=2
first term a=1
an=a+(n-1)d
2n-1=1+(l-1)2
2n-1=1+2l-2
2n-1=2l-1
l=n
(i used l for number of terms)
number of terms=n
Answer:
The second one
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
For any given function, all first input values (x-values/coordinates) in the relation are considered as the domain values. While the output values (y-values/coordinates) make up the range of the given function.
The mapped relation that has a domain of {1,2,3}, is the mapped relation that has 1, 2, and 3 on the input side on our left.
Therefore, the mapped relation in option C is the answer.
The first step to solving a story problem is identifying variables. For this problem, I will identify the variables as:
D = Drew's age
J = Jimmy's age
Once the variables are identified, we need to find as many equations as we have variables. Since we have two variables, we will have to write two equations.
Since Drew is 3 years younger than Jimmy: D + 3 = J
Since the sum of the brothers' ages is 21: D + J = 21
Once I have two equations is two variables, I can solve the system using either substitution method or elimination method. For this problem, I will use substitution method.
D + J = 21 Equation 2
D + (D + 3) = 21 Substitution of value of J from equation 1 into equation 2
D + D + 3 = 21 Associative property of addition
2D + 3 = 21 Simplify
2D + 3 - 3 = 21 - 3 Subtract 3 from each side
2D = 18 Simplify each side
2D/2 = 18/2 Divide each side by 2
D = 9 Simplify each side
Now that we have D, we can substitute it into equation 1 to get the value of J
D + 3 = J Equation 1
9 + 3 = J Substitution
12 = J Simplify
