How do you write an equation of a line that is parallel line to y=8x-8 through the point (5,2)

1 answer:

8 0

Parallel means that the two equations have the same slope,

so we have y = 8x + b so far.

Then we can just apply the slope to the given point by taking the y value and decreasing it by 40, due to the x value being 5

So in short, the equation that runs parallel to y = 8x-8 and intersect the point (5,2) is y = 8x -38

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If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?

svetlana [45]

Answer:

<em>B</em> $(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)$

Step-by-step explanation:

<u>Dilations</u>

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

The y-coordinate of E is 2 and the y-coordinate of E' is 5. This gives us the same scale factor for the y-axis of 5/2.

Thus, the rule to dilate the pentagon is:

B $\mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}$