Answer:
<u>Answer</u><u> </u><u>is</u><u> </u><u>1</u><u>/</u><u>6</u>
Step-by-step explanation:

Answer:
a: 0.8884
b: 0.9934
Step-by-step explanation:
We have µ = 300 and σ = 70. The sample size, n = 125.
For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:
P(292 < x < 308).
We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.
We have P(292 < x < 308) = 0.8884
Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317. We want to find
P(283 < x < 317)
We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.
We have P(283 < x < 317) = 0.9934
This answer uses NMF, which you can find out about on my profile:
Preliminary work:
Following the BIDMAS order of operations, we can calculate part of it already, and that's the 2•4, which equals 8.
Therefore, the equation now reads:
8+x = y
x = 5:
8+5 = 13
13 ≠ 16
13 ≠ y
x = 4:
8+4 = 12
12 = 12
12 = y
Therefore, the pair is (4, 12)
Answer:
208
Step-by-step explanation:
Given that;
Given that;
y= a(1 - b)^t
Where;
wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.
To obtain the constant b,
y= ae^-bt
Substituting values;
1000 = 3000 e^-b(50)
1000/3000 = e^b(50)
0.33 = e^b-(50)
ln (0.33) = ln(e^b(-50))
-1.1 = -50b
b= 1.1/50
b= 0.022
After two hours or 120 minutes;
y= 3000(1 - 0.022)^120
y= 207.8661772
y= 208
Answer:
174m²
Step-by-step explanation:
SA = 2(wl + hl + hw)
= 2(5m x 11m + 2m x 11m + 2m x 5m)
= 2(55m² + 22m² + 10m²)
= 2 x 87m²
=174m²//