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dem82 [27]
3 years ago
12

Because of a virus introduced into a bacterial culture, the population of the bacteria decreasedfrom 3000 to 1000 in 50 minutes.

Assuming exponential decay, determine how many bacteriawill remain after 2 hours from the beginning of the experiment.(Note: First give an exactanswer, then round it to the nearest integer.)
Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

208

Step-by-step explanation:

Given that;

Given that;

y= a(1 - b)^t

Where;

wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.

To obtain the constant b,

y= ae^-bt

Substituting values;

1000 = 3000 e^-b(50)

1000/3000 = e^b(50)

0.33 = e^b-(50)

ln (0.33) = ln(e^b(-50))

-1.1 = -50b

b= 1.1/50

b= 0.022

After two hours or 120 minutes;

y= 3000(1 - 0.022)^120

y= 207.8661772

y= 208

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Please help with my questions...
FrozenT [24]

Answer:

20 X 1/20 = 1

10 X 1/10 = 1

Step-by-step explanation:

I hope that helps.

7 0
3 years ago
What is the answer to (4m-5) - (6m-7+2n)
Yanka [14]
Work:
4m-6m=-2m
-5-(-)7=-5+7=2
Answer: -2m+2+2n
Hope this helps
4 0
4 years ago
What is the 10th term in -9,-6,-1,6,15
levacccp [35]

Answer:

90

Step-by-step explanation:

This is an increasing sequence, with -9 as its first term. The first increase is +3, then +5, +7, and +9. The differences increase by 2 each time. The sixth term will be 15 + 11, and the seventh would be 15 + 11 + 13. We can follow this pattern to get to the tenth term. 15 + 11 + 13 + 15 + 17 + 19 = 90

7 0
3 years ago
What are the domain,range, and asymptote of h(x)=2x + 4
GREYUIT [131]
This is a linear function, so there is NO asymptote.  The slope is 2 and the y-intercept is 4.  Since this is a polynomial, the domain is "the set of all real numbers," and the range is also that.
3 0
3 years ago
Read 2 more answers
Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
Aloiza [94]

Answer:

0.70275

Step-by-step explanation:

Data provided in the question:

4e²ˣ⁻¹ -1 = 5

now solving for 'x'

⇒ 4e²ˣ⁻¹ = 5 + 1

or

⇒ 4e²ˣ⁻¹ = 6

or

⇒ e^{(2x-1)} =\frac{6}{4}

or

⇒ e^{(2x-1)} =\frac{3}{2}

now,

taking natural log both sides, we get

⇒ 2x - 1 = \ln(\frac{3}{2})

also,

we know

⇒ \log(\frac{A}{B}) = \log(A)+\log(B)

thus,

⇒ 2x - 1 = ln(3) - ln(2)

or

⇒ 2x - 1 = 1.0986 - 0.6931

or

⇒ 2x - 1 = 0.4055

or

⇒ 2x = 0.4055 + 1

or

⇒ 2x = 1.4055

or

⇒ x = 0.70275

3 0
3 years ago
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