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ElenaW [278]
3 years ago
10

What is the interquartile range of the data displayed in this box-and-whisker plot? box-and-whisker plot ranging from 34 to 58 w

ith ticks at increments of 1. plot defined by points at 35, 42, 49, 54, 57. a box runs from 42 to 54.
Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer: The interquartile range= 12


Step-by-step explanation:

From the given the lower quartile Q_1= 42

the middle quartile Q_2= 49

The upper quartile Q_3= 54

We know that the  interquartile range is given by:=-

Interquartile range= upper quartile- lower quartile or Q_3-Q_1

⇒\text{Interquartile range (IQ)}=54-42=12

Hence, the interquartile range of the data displayed in this box-and-whisker plot is 12.


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40pts!! Select the correct answer. <br> Simplify.
stiv31 [10]

Hey!

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Solution:

=\frac{3x^2y^3}{z^3}

Cube the coefficients.

= \frac{27x^2y^3}{z^3}

Multiply the exponents.

= \frac{27x^6y^9}{z^9}

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Answer:

Option D.

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Hope This Helped! Good Luck!

5 0
3 years ago
If the 50th and 51st terms of an arithmetic sequence are 140 and 142, find the 1st term
morpeh [17]

Answer:

The first term is 42.

Step-by-step explanation:

The common difference is 142  - 140 = 2 so we have

50th term = a1 + 2(50 -1) = 140    where a1 is the first term

a1 + 98 = 140

a1 = 140 - 98 =  42.

4 0
3 years ago
Solve for m. 99pt reward and brainliest
Kamila [148]
-37m = 12

plug in the numbers:

(-28)(-37) ≠ 12

(-26)(-37)≠12

(26)(-37)≠12

(28)(-37) ≠ 12


idk none of the given answers are correct. Sorry.
8 0
3 years ago
Find the probability of drawing 3 Aces at random from a deck of 52 ordinary playing cards if the cards are:_________
Minchanka [31]

Answer:

A) 1/2197

B) 1/5525

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome.

Since there are 52 random cards in a deck of card, the total outcome will be 52.

a) Also in a deck of card, there are 4 aces. If we are to select 3 aces with replacement, this means that each time we pick up an ace from the card, it was returned.

Pr(drawing an ace) = 4/52

Pr(drawing 3 aces and replacing it) = 4/52 *4/52*4/52

Pr(drawing 3 aces and replacing it) = 64/140,608

Pr(drawing 3 aces and replacing it) = 1/2197

b) If we pick 3 aces without replacement then each time we pick an ace, the total number cards keeps reducing.

Pr(picking the first ace) = 4/52

Pr(picking the second ace without replacing) = 3/51 (Since we didn't replace the first one, the total ace in the deck of card will reduce to 3 and the total will be 51)

Pr(picking the third ace without replacing) = 2/50 (since we didn't replace the first two aces, the total ace in the deck of card will reduce to 2 and the total will be 50)

Pr(drawing 3 aces without replacement) =  4/52*3/51*2/50

Pr(drawing 3 aces without replacement) =  24/132,600

Pr(drawing 3 aces without replacement) = 1/5525

5 0
3 years ago
How many solutions does the system have? \begin{cases} 3x+y=8 \\\\ 2x+2y=8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 3x+y=8 2x+2y=8 ​ Choose 1
ELEN [110]

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

3x+y=8 (1)

2x+2y=8 (2)

Let's multiply the first equation by 2 and subtract it to the second equation  

6x-2x+2y-2y=16-8

4x=8  

x=2

Using this value in (1) we can find y.

3(2)+y=8

6+y=8

y=2

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

3 0
3 years ago
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