Question

Simplify the product. 2p(–3p2 + 4p – 5)

Answer 1

Hope this helped you :)

Answer 2

Answer: $2p(-3p^2+4p-5)=-6p^3+8p^2-10p$

Step-by-step explanation:

Given expression: $2p(-3p^2+4p-5)$

We can use distributive property which says that:_

$a(b+c)=ab+ac$, where a ,b and c be any real numbers or variables.

Then,  $2p(-3p^2+4p-5)=2p\cdot-3p^2+2p\cdot4p-2p\cdot5$

$=-6p^{1+2}+8p^{1+1}-10p$

Now, we use product law of exponent which says that:-

$a^m\times a^n=a^{m+n}$

$\Rightarrow\ -6p^{1+2}+8p^{1+1}-10p=-6p^3+8p^2-10p$

Hence, $2p(-3p^2+4p-5)=-6p^3+8p^2-10p$