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yulyashka [42]
4 years ago
10

3(t−2)=−1 What value of t t makes the following equation true?

Mathematics
1 answer:
pashok25 [27]4 years ago
4 0

Answer:

t=5/3

Step-by-step explanation:

in order to get our answer, we have to first open it up which comes to 3t-6=-1

next,we have to isolate the variable, so we add (6) to (-1)

then we get 3t=5

so, t=5/3

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trapecia [35]

Answer: ( D) 998 is the greatest three digit positive integer

Step-by-step explanation: Your welcome.

7 0
2 years ago
A theater seats 2,816 people. The first row has 26 seats while the last row has 150 seats. Assuming the number of seats per row
wolverine [178]

Answer:

The theater has 32 rows

Step-by-step explanation:

The rule of the sum of n terms of an arithmetic sequence is S_{n} = \frac{n}{2} (a + l), where

  • a is the first term
  • l is the last term
  • n is the number of the terms

∵ The number of seats per row follows an arithmetic sequence

∵ The first row has 26 seats

∴ a = 26

∵ The last row has 150 seats

∴ l = 150

∵ The theater seats are 2,816

∴ S_{n} = 2,816

→ Substitute these values in the rule of the sum above to find n

∵ 2,816 = \frac{n}{2}(26 + 150)

∴ 2,816 = \frac{n}{2}(176)

∴ 2,816 = 88n

→ Divide both sides by 88

∴ 32 = n

∵ n represents the number of the rows

∴ The theater has 32 rows

3 0
3 years ago
Please help I can’t figure this out!
Monica [59]

Explanation:

All values in the x-column get filled with -2.

The graph is the vertical line, x = -2.

__

You are told x=-2. There is nothing to figure out. The value of y is irrelevant.

That equation describes a vertical line. The points on the line have x-coordinate -2, and any (every) y-coordinate.

4 0
2 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
Part 2 of Question please help me <br> and thank you for your help
san4es73 [151]

1 tick represents 8 units

4 0
2 years ago
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