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3 years ago

If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p circle q) (x)?

1 answer:

6 0

Solution:

(p o q) = p(q(x))
p(q(x)) = 2(x - 3)^2 - 4(x - 3)
======= 2(x - 3)(x - 3) - 4(x - 3)
======= 2(x^2 - 6x + 9) - 4(x -3)
(p o q) = 2x^2 - 10x + 30
(p o q) = 2[x^2 - 5x + 15]

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The Hamilton Brush Company issued 2,500 shares of common stock worth $100,000.00 total. What is the par value of each share?

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3 years ago

Which is the graph of linear inequality 6x + 2y > –10? NO PICTURES PLZZ

kvasek [131]

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Step-by-step explanation:

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2 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

$m_ {1} * m_ {2} = - 1$

The given line is:

$5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3$

So we have:

$m_ {1} = \frac {5} {2}$

We find $m_ {2}:$ $m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}$

So, a line perpendicular to the one given is of the form:

$y = - \frac {2} {5} x + b$

We substitute the given point to find "b":

$-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2$

Finally we have:

$y = - \frac {2} {5} x-2$

In point-slope form we have:

$y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)$

ANswer:

$y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)$

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3 years ago

Read 2 more answers

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777dan777 [17]

Answer:

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Step-by-step explanation:

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2 years ago

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vova2212 [387]

Answer:

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