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Umnica [9.8K]
3 years ago
5

Evaluate at the given value 4x^2+6x-5 when x=-3

Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0
To evaluate 4x² + 6x - 5 when x = -3, plug -3 for x into the expression.

Evaluate when x = -3.
4x² + 6x - 5

Plug -3 for x.
4(-3)² + 6(-3) - 5

Square -3.
4(9) - 18 - 5

Multiply 4 and 9.
36 - 18 - 5

Subtract from left to right.
18 - 5
13

Answer:
13
malfutka [58]3 years ago
4 0
That is 4(-3)^2 + 6(-3) - 5  =   36 - 18 - 5 =   13 Answer
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There are 8 yellow and 24 blue. Our ratio from yellow to blue is 8:24.
To simplify this, we need to see if we can divide 8 and 24 by a common factor.
8 and 24 can be divided by 8, so let's do that.
8/8 = 1.
24/8 = 3.
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C.) is your correct answer.
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
3 years ago
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