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3 years ago

4p5 - p3 + p2 + 11 what is the degree and amount of terms?

Mathematics

1 answer:

marishachu [46]3 years ago

7 0

Is p5 really p^5?????????????

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2 years ago

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2 years ago

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Vesnalui [34]

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3 years ago

Solve h = −16t2 + 36t + 4.

kvasek [131]

I can do each of the things I asked above.
So, let's change this into vertex form:
$h=-16t^2+36t+4$
$h=(-16t^2+36t)+4$
$h=-16(t^2-2.25t)+4$
$h=-16(t^2-2.25t+1.27-1.27)+4$
$h=-16(t^2-2.25t+1.27)+20.32+4$
$h=-16(t-1.125)^2+24.32$
The vertex is at (1.125,24.32)
Answers may vary due to rounding

Factored Form:
$h = -16t^2 + 36t + 4$
$h = -4\left(4t^2-9t-1\right)$

Quadratic Formula:
$x = \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}$
h = -16t^2 + 36t + 4
a = -16 b = 36 c = 4
$h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}$
$h = \frac{-36 +/- \sqrt{1552}}{-32}$
$h = ≈-0.11$
$h = ≈2.36$

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3 years ago

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kkurt [141]

Answer:

100 1/4

Step-by-step explanation:

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3 years ago