4p5 - p3 + p2 + 11 what is the degree and amount of terms?

Find the area of a rhombus having perimeter 80 em and one diagonal 24 cm.

horsena [70]

A=384 cm^2 hope this helped!

4 0

3 years ago

Function A is a quadratic function with a vertex at (3, 4) and a leading coefficient of -1 Function B has the equation y = |x +

skad [1K]

With the information given, we deduce that the parabola is

$y=-(x-3)^2+4 = -(x^2-6x+9)+4 = -x^2+6x-5$

Reflecting a function over the x axis means to change its sign. After the reflection, the parabola becomes

$y=x^2-6x+5$

And to shift down a function, you subtract the shift from the equation: the equation becomes

$y=x^2-6x+5-2=x^2-6x+3$

Similarly, the other function is reflected over the x axis (sign change) and shifted up 3 (add 3 to the equation):

$|x+2|\mapsto -|x+2|\mapsto -|x+2|+3$

In order to compute the y intercept, we simply have to evaluate the functions at x=0: for the parabola we have

$y(0)=3$

For the other function, we have

$y(0)=-|2|+3=-2+3=1$

8 0

4 years ago

The variable, y, varies directly with x. if y = 20 when x = 25, what is y when x = 43? Also please explain so I can understand t

Gwar [14]

Answer:

25

Step-by-step explanation:

4 0

2 years ago

The solution for the following system of equations is shown on the graph. What is the solution?

Bingel [31]

The solution is (3 , 4) ⇒ 2nd answer

Step-by-step explanation:

The system of equations can be solved by:

Elimination method
Substitution method

The system of equations is:

y = 3 x - 5 ⇒ (1)

y = $\frac{1}{3}$ x + 3 ⇒ (2)

By using the substitution method substitute y in equation (2) by equation (1)

3 x - 5 = $\frac{1}{3}$ x + 3

Subtract $\frac{1}{3}$ x from both sides

$\frac{8}{3}$ x = 8

Divide both sides by $\frac{8}{3}$

x = 3

substitute x by 3 in equation (1)

y = 3(3) - 5

y = 9 - 5

y = 4

The solution is (3 , 4)

Learn more:

You can learn more about the system of equations in brainly.com/question/6075514

#LearnwithBrainly

5 0

4 years ago

1 2 3 4 5 6 7 8 9 10 TIME REMAINING 52:51 Use the data set to determine which statements are correct. Check all that apply. 35,

Nady [450]

Answer:

The true statements are:

The median is 38.5.
There is an outlier.
The lower quartile is 29.
The upper quartile is 70.
The interquartile range is 41.

Step-by-step explanation:

The given data are: 35, 41, 18, 75, 36, 21, 62, 29, 154, 70

Make the data in order from the least to the greatest

18 , 21 , 29 , 35 , 36 , 41 , 62 , 70 , 75 , 154

So, the median of the data = (36 + 41)/2 = 38.5

We can deduce that The number 154 represents an outlier because the difference between 154 and 75 is much greater than the difference between the other data

If we divided the data to two groups , they will be:

(18 , 21 , 29 , 35 , 36) , (41 , 62 , 70 , 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

And the interquartile range = Q2 - Q1 = 70 - 29 = 41

So, the true statements are:

The median is 38.5
There is an outlier
The lower quartile is 29
The upper quartile is 70
The interquartile range is 41.

7 0

4 years ago