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Hi there!
Solving th' Inequality :-
4y + 3 > 24 + 14
=> 4y + 3 > 38
=> 4y > 38 - 3
=> 4y > 35
=> y >
=> y > 8.75
Therefore, all real number y which are greater than 8.75 are the solutions of th' given Inequality.
Hence,
Solution of the following Inequality is : ( 8.75, ∞ )
~ Hope it helps!
Solving th' Inequality :-
4y + 3 > 24 + 14
=> 4y + 3 > 38
=> 4y > 38 - 3
=> 4y > 35
=> y >
=> y > 8.75
Therefore, all real number y which are greater than 8.75 are the solutions of th' given Inequality.
Hence,
Solution of the following Inequality is : ( 8.75, ∞ )
~ Hope it helps!
The relative frequency for the third class, 60 - 69 is equal to 12%.
<h3>What is a class width?</h3>In a frequency distribution table, a class width can be defined as the difference between the upper (maximum) and lower (minimum) boundaries of any class in a data set. This ultimately implies that, all classes must all have the same width in a frequency distribution table.
<h3>What is a frequency table?</h3>A frequency table can be used to graphically represent the frequencies or relative frequencies that are associated with a categorical variable.
<h3>How to calculate the relative frequency for the third class, 60 - 69?</h3>First of all, we would determine the total number of frequency as follows:
Total frequency = 12 + 11 + 6 + 10 + 11
Total frequency = 50.
Mathematically, relative frequency can be calculated by using this formula:
Relative frequency = class frequency/total frequency × 100
Relative frequency = 6/50 × 100
Relative frequency = 0.12 × 100
Relative frequency = 12%.
Read more on frequency table here: brainly.com/question/20744563
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Complete Question:
You would like to build a relative frequency distribution for this data set to easily compare it to another class of students.
What is the relative frequency for the third class, 60 - 69?
