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ipn [44]
2 years ago
13

HELP WITH NUMBER 13 please

Mathematics
1 answer:
amid [387]2 years ago
4 0

Answer: QE = 10

Step-by-step explanation: To solve this problem, it's important to understand that the diagonals of a parallelogram bisect each other.

This means that E is the midpoint of diagonal SQ.

So we can setup the equation x² + 9x = 4x + 6.

To solve this polynomial equation, set it equal to zero first.

So we have x² + 5x - 6 = 0 and we get (x + 6)(x - 1) = 0

when we factor the left side of the equation.

So this means that x = -6 or x = 1.

However, -6 will give us a negative length when we plug it in

to find QE so this will not work.

However, plugging 1 in will give us 10 as a length so QE = 10.

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Find the percent of change. Where necessary, round to the nearest percent. Describe the percent of change as a percent of increa
deff fn [24]
70.17543859649122 percent change , rounded would be 70%, it is a 70% increase, as it goes to 57,000 to 97,000
6 0
3 years ago
Jensen Tire & Auto is in the process of deciding whether to purchase a maintenance contract for its new computer wheel align
sasho [114]

Answer:

Step-by-step explanation:

Hello!

The given data corresponds to the variables

Y:  Annual Maintenance  Expense ($100s)

X: Weekly Usage  (hours)

n= 10

∑X= 253; ∑X²= 7347; \frac{}{X}= ∑X/n= 253/10= 25.3 Hours

∑Y= 346.50; ∑Y²= 13010.75; \frac{}{Y}= ∑Y/n= 346.50/10= 34.65 $100s

∑XY= 9668.5

a)

To estimate the slope and y-intercept you have to apply the following formulas:

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{9668.5-\frac{253*346.5}{10} }{7347-\frac{(253)^2}{10} }= 0.95

a= \frac{}{Y} -b\frac{}{X} = 34.65-0.95*25.3= 10.53

^Y= a + bX

^Y= 10.53 + 0.95X

b)

H₀: β = 0

H₁: β ≠ 0

α:0.05

F= \frac{MS_{Reg}}{MS_{Error}} ~~F_{Df_{Reg}; Df_{Error}}

F= 47.62

p-value: 0.0001

To decide using the p-value you have to compare it against the level of significance:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The decision is to reject the null hypothesis.

At a 5% significance level you can conclude that the average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

b= 0.95 $100s/hours is the variation of the estimated average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

a= 10.53 $ 100s is the value of the average annual maintenance expense of the computer wheel alignment and balancing machine when the weekly usage is zero.

c)

The value that determines the % of the variability of the dependent variable that is explained by the response variable is the coefficient of determination. You can calculate it manually using the formula:

R^2 = \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{[sumY^2-\frac{(sumY)^2}{n} ]} = \frac{0.95^2[7347-\frac{(253)^2}{10} ]}{[13010.75-\frac{(346.50)^2}{10} ]} = 0.86

This means that 86% of the variability of the annual maintenance expense of the computer wheel alignment and balancing machine is explained by the weekly usage under the estimated model ^Y= 10.53 + 0.95X

d)

Without usage, you'd expect the annual maintenance expense to be $1053

If used 100 hours weekly the expected maintenance expense will be 10.53+0.95*100= 105.53 $100s⇒ $10553

If used 1000 hours weekly the expected maintenance expense will be $96053

It is recommendable to purchase the contract only if the weekly usage of the computer is greater than 100 hours weekly.

4 0
3 years ago
L
Effectus [21]

Answer:

Step-by-step explanation:

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PLEASE HELP!!!! ASAP ALMOST DUE
lions [1.4K]

Answer:

idk im not that smart

Step-by-step explanation:

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Answer:

Sale 2/3

Step-by-step explanation:

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