Answer:

The confidence interval is 95% and the significance level is
and
and the critical value would be:

And the margin of error would be:
Step-by-step explanation:
We have the following info given:
the sample size selected
the number of people who lease a car
the estimated proportion of people who lease a car
The margin of error is given by:

The confidence interval is 95% and the significance level is
and
and the critical value would be:

And the margin of error would be:

f(4)= 4^2 - 1 = 15
g(f(4)) = g(15) = 2(15) = 30
Hope this helps!
4/7 because the equation would be 2(7-5)
over
5+2
so it would be
2(2)
over
7
and then it would be
4
over
7
System of Equations
For the problem to solve we'll use the following variables:
x = number of the early bird tickets sold
y = number of the regular tickets sold
Haley sold a total of 20 tickets, thus:
x + y = 20 [1]
Early bird tickets cost $10 and regular tickets cost $15, thus the total money collected is:
10x + 15y = 225
Dividing by 5:
2x + 3y = 45 [2]
We have to solve the system of equations [1] and [2].
Multiply [1] by -2:
-2x - 2y = -40 [3]
Add [3] to [2]:
-2x - 2y +2x + 3y = -40 + 45
Simplifying:
y = 5
Substituting in [1]:
x + 5 = 20
Subtracting 5:
x = 20 - 5
x = 15
Solution: Hayley sold 15 early bird tickets and 5 regular-priced tickets
The order pair solution is (15,5)