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2 years ago

How do I put these equations into vertex form?

Mathematics

1 answer:

kenny6666 [7]2 years ago

4 0

I found my notes for this exact paper and I have that first problem written. hopefully this helps

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3 years ago

The length of a rectangular plot of land is 1Start Fraction 17 over 25 End Fraction times its width. If the width of the plot is

butalik [34]

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2 years ago

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Can you solve this for me by:

Slav-nsk [51]

$2a^2-32$

$2*a^2-2*16$

$2*(a^2-16)$

but we have a Difference of two square

$x^2-y^2=(x+y)*(x-y)$

now you can see it very well

$2*(a^2-4^2)$

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$\boxed{\boxed{2*(a-4)*(a+4)}}$

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2 years ago

HELP ASAP!!! 74 POINTS AND BRAINLIEST!!!!

Mice21 [21]

Answer:

the first one goes in the botten and the 2nd one goes into top 3rd goes into bottem.

Step-by-step explanation:

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2 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

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2 years ago