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2 years ago

What is the solution to the following system

Mathematics

1 answer:

Afina-wow [57]2 years ago

4 0

Answer:

I belive it's B

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On a normal day, I can walk from my house to school in three quarters of an hour. The return trip takes me the same amount of ti

Likurg_2 [28]

Answer:

208 1/8 hours

Step-by-step explanation:

The amount of time saved on each trip is ...

(3/4 h) - (1/4)(3/4 h) = (3/4)(3/4 h) = 9/16 h

There are 2×5×37 = 370 trips in the school year, so the total savings in time is about ...

370×(9/16 h) = 208 1/8 h

4 0

3 years ago

Solve for x.<br> 0 < 3x - 6 s 18<br> 0 2 x<0 or x >8<br> x<2 or x > 8

docker41 [41]

Answer:

Step-by-step explanation:

4 0

3 years ago

1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound

Drupady [299]

Answer:

Step-by-step explanation:

Thinking process:

$\int\limits^a_b {cF} \, .dr$

= $\int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx curlFdS$ by Stoke's Theorem

= $\int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< z_x,-z_y, 1 > dA\\= \int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< 2x, 2y, 1 > dA$ since z = $25-x^{2} -y^{2} \\= 0$

3 0

3 years ago

A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0

2 years ago

Can you help please no links or point stealing or I will report

valentina_108 [34]

1.A school assembly has 179 students in it. Nine teachers escort "k" number of

students out of the assembly, until there are 26 students remaining.

2. a i guess

5 0

3 years ago

Read 2 more answers