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3 years ago

I think it is a and c, but I would feel better if I had confirmation lol

Mathematics

2 answers:

mars1129 [50]3 years ago

5 0

Answer:

A is correct and so is D (C = 64b + 16c, but it is meant to be -16)

Step-by-step explanation:

Hope this helps! Please mark as Brainliest!

Aleonysh [2.5K]3 years ago

5 0

It’s is A and D if u would really like two know

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What is the volume of a cylinder with a diameter of 14 cm and a height of 4 cm.

malfutka [58]

Radius= 7cm
Base area= 49pi
Volume= 49pi*4= 196pi=615.75cm^3

8 0

3 years ago

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

3 years ago

Juan piensa en un número si al doble del

Annette [7]

Answer:

Step-by-step explanation:

el número es 4,5

es una ecuación lineal:

2x+18=27

2x=9

x=9/2

x=4,5

3 0

3 years ago

Read 2 more answers

If point D is the midpoint of segment BC then what are the coordinates of point D given B(5,-2) and C (-7,-2)

Neko [114]

Point d is at (-1, -2) find the average of the values to get the midpoint

5 0

3 years ago

6300 and 530, 3 and 2 underlined Compare value The value 3 in____ is _____times

topjm [15]

Basically when reading the value of a digit we start from the right.
Digits from the right to the left are named as follows:
units......>no zeros/digits after them
tens......> 1 zero/digit after the digit
hundreds.......> 2 zeros/digits after the digit
thousands......> 3 zeros/digits after the digit
ten thousands.......> 4 zeros/digits after the digit
hundred thousands.........> 5 zeros/digits after the digit
million........> 6 zeros/digits after the digit

Applying this on the above mentioned numbers, we will find that the 3 represents the hundreds (300) in 6300 while it represent the tens (30) in 530.

The question is to find the difference between the two, which means we will subtract them:
difference = 300 - 30 = 270

The value 3 in 6300 is 270 times the value of 3 in 530

5 0

3 years ago