arrange the circles (represented by their equations in general form) in ascending order of their radius lengths, x^+y^-2x+2y-1=

Question

3 years ago

7

arrange the circles (represented by their equations in general form) in ascending order of their radius lengths, x^+y^-2x+2y-1=

0, x^+y^-4x+4y-10=0, x^+y^-8x-6y-20=0, 4x^+4y^+16x+24y-40=0, 5x^+5y^-20x+30y+40=0, 2x^+2y^-28x-32y-8=0, x^+y^+12x-2y-9=0.

Mathematics

1 answer:

Lubov Fominskaja [6] · Answer 1 · 2022-05-01T22:48:42+03:00

Lubov Fominskaja [6]3 years ago

7 0

From the order you gave me in the question the answer is equation number
4 1 3 2 6 5
Those are the equation numbers in ascending order based on their radius lengths