A] David's speed during the period:
i] AB
speed=distance/time
time taken between AB=0.5 hours
distance=20 km
thus
speed=20/0.5=40 km/h
ii]BC
time taken between BC=1.5 hours
distance=20
speed=20/1.5=13 1/3 km/h
b] Average speed for the entire time will be:
average speed=(total distance)/(total time)
total distance=(20+20+20)=60 km
total time=3 hours
thus
average speed=60/3=20 km/h
c] David's distance 2 hours and 15 minutes from the starting point was:
distance=20+20+10=50 km
Answer:
graphic attached
Step-by-step explanation:
Hi
when t = 0 then s (t) = 1/4
when t tends to infinity then s (t) tends to 0
when t tends to infinity then s (t) tends to infinity
the function has a horizontal asymptote at y = 0
Success with your homework
Undefined as the line is parallel to y axis ie; x=3
Answer:
23/4
Step-by-step explanation:
This means that it is 3/4 of the distance in the x <u>and</u> y coordinates, so it is 3/4 of the way from 2 to 7, and since this is a difference of 7-2=5, then it is 2 + (5 * 3/4) or 2 + 15/4 or 23/4.
one hour 55 min
you just need to subtract bout to get the answer
