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spayn [35]
3 years ago
8

Add And Simplify.

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0
The answer is A

-4x +3y + z + 2
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Problem 1: Write each expression in the form a^b, without using any radicals.
VARVARA [1.3K]

By radical do you mean the square root symbol?

7 0
3 years ago
Please help me ill give brainiest
timofeeve [1]

Answer:    i think it is C

Step-by-step explanation: hpoe that helps!!!! :)

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4 years ago
Hiii please help!! i'll give brainiest if you get it correct - find the volume.
ddd [48]

Answer:

Step-by-step explanation:

volume=area of side triangle×distsnce between triangles

=1/2×20×8×5

=400 in³

5 0
3 years ago
Read 2 more answers
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of ​$20. Opt
sdas [7]

Answer:

40$

Step-by-step explanation:

they have

20$

5%

40hours

i=prt

multiplication of both

=40×20×5/100

=40$

the amount required at the week is 40$

7 0
3 years ago
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