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3 years ago

Is this a liner equation ,the price of a loaf of bread increases by .25 each week

Mathematics

1 answer:

alexgriva [62]3 years ago

5 0

i think its not because it should increase so it would go diagonal

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What are the means and standard deviations for correct answers from attending a review session

Iteru [2.4K]

The mean from attending a review session will be the average of the numbers that are given.

Your information is incomplete. Therefore, an overview will be given. Mean simply means average.

For example, if the given numbers are 2, 4, 6, and 10. The mean will be:

= (2 + 4 + 6 + 10)/4

=22/4

= 5.5

Learn more about mean on:

brainly.com/question/1136789

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7 0

2 years ago

Mike bungee jumped from a building with eight stories. Each story was 15 4/5 feet in height. How tall was the building?

r-ruslan [8.4K]

126 2/5 i multiplied them separately and added the two products together

5 0

4 years ago

29x+2=31<br> Giving brainliest if do correct..<br> Explanation also or reported

olasank [31]

Answer:

x = 1

Step-by-step explanation:

29x + 2 = 31

-2 -2

29x = 29

----- -----

29 29

x = 1

8 0

3 years ago

What’s the area of this polygon answer ASAP my teacher died

Anastasy [175]

Answer:

Break it into 2 sections: 18 by 3 and 6 by 20

area = 54 + 120

= 174 (answer is A.)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Sorry if this is too much but I'm desperate right now.

zalisa [80]

Answer:

$f(x)=\dfrac{2x-1}{x+2}\\ \\f^{-1}(x)=\dfrac{-2x-1}{x-2}$

$f(x)=\dfrac{x-1}{2x+1}\\ \\f^{-1}(x)=\dfrac{-x-1}{2x-1}$

$f(x)=\dfrac{x+2}{-2x+1}\\ \\f^{-1}(x)=\dfrac{2-x}{-2x-1}=\dfrac{x-2}{2x+1}$

$f(x)=\dfrac{2x+1}{2x-1}\\ \\y=f^{-1}(x)=\dfrac{1+x}{2(x-1)}$

$f(x)=\dfrac{x+2}{x-1}\\ \\f^{-1}(x)=\dfrac{x+2}{x-1}$ - extra

Step-by-step explanation:

$f(x)=y=\dfrac{2x-1}{x+2}\\ \\y(x+2)=2x-1\\ \\yx+2y=2x-1\\ \\yx-2x=-1-2y\\ \\x(y-2)=-1-2y\\ \\x=\dfrac{-1-2y}{y-2}\\ \\y=f^{-1}(x)=\dfrac{-2x-1}{x-2}$

$f(x)=y=\dfrac{x-1}{2x+1}\\ \\y(2x+1)=x-1\\ \\2xy+y=x-1\\ \\2xy-x=-1-y\\ \\x(2y-1)=-1-y\\ \\x=\dfrac{-1-y}{2y-1}\\ \\y=f^{-1}(x)=\dfrac{-x-1}{2x-1}$

$f(x)=y=\dfrac{x+2}{-2x+1}\\ \\y(-2x+1)=x+2\\ \\-2xy+y=x+2\\ \\-2xy-x=2-y\\ \\x(-2y-1)=2-y\\ \\x=\dfrac{2-y}{-2y-1}\\ \\y=f^{-1}(x)=\dfrac{2-x}{-2x-1}=\dfrac{x-2}{2x+1}$

$f(x)=y=\dfrac{2x+1}{2x-1}\\ \\y(2x-1)=2x+1\\ \\2xy-y=2x+1\\ \\2xy-2x=1+y\\ \\x(2y-2)=1+y\\ \\x=\dfrac{1+y}{2y-2}\\ \\y=f^{-1}(x)=\dfrac{1+x}{2(x-1)}$

$f(x)=y=\dfrac{x+2}{x-1}\\ \\y(x-1)=x+2\\ \\xy-y=x+2\\ \\xy-x=2+y\\ \\x(y-1)=2+y\\ \\x=\dfrac{2+y}{y-1}\\ \\y=f^{-1}(x)=\dfrac{x+2}{x-1}$

3 0

3 years ago