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alexgriva [62]
3 years ago
15

60 cans of soup are arranged to be displayed in 10 rows. Why does the fraction 10 over 60 not represent this situation? Explain.

Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

<u><em>Explanation</em></u>: The reason why is because when divide 10/60 it becomes a decimals and cans can't be decimals, but if you divide 60/10 then it will be 6 cans in each row.

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Solve for g.<br> 9 - g = 2g
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Answer:

g=3

Step-by-step explanation:

9 - g = 2g

+g       +g

9=3g

divide both sides by 3

g=9

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3 years ago
4/5(20e - 5q) - 1/9(-27q + - 18e)<br><br>help
Lady bird [3.3K]

Answer: =−q+48.929073 <-- coming frm a calculator lol

Step-by-step explanation:

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2 years ago
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A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
2 years ago
Paige has 3 rain coats, a pink one, a red one, and a yellow one. She has blue rain boots, green rain boots, and 1 yellow umbrell
Harlamova29_29 [7]
The combination is 4/12
4 0
3 years ago
A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
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