Answer:
g=3
Step-by-step explanation:
9 - g = 2g
+g +g
9=3g
divide both sides by 3
g=9
Answer: =−q+48.929073 <-- coming frm a calculator lol
Step-by-step explanation:
Answer:
Systolic on right

Systolic on left

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.
Step-by-step explanation:
Assuming the following data:
Systolic (#'s on right) Diastolic (#'s on left)
117; 80
126; 77
158; 76
96; 51
157; 90
122; 89
116; 60
134; 64
127; 72
122; 83
The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

And the best estimator is 
Systolic on right
We can calculate the mean and deviation with the following formulas:
[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

For this case we have the following values:

So then the coeffcient of variation is given by:

Systolic on left
For this case we have the following values:

So then the coeffcient of variation is given by:

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The weight of the bucket is 
The depth of the well is 
The weight of the water is 
The rate at which the bucket with water is pulled is 
The rate of the leak is 
Generally the workdone is mathematically represented as
]
Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

Here I is the rate of water loss in lb/ft mathematically represented as

=> 
=>
So

=> 
So
]
=> ![W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.](https://tex.z-dn.net/?f=W%20%3D%20%20%5B47x%20-%20%5Cfrac%7B0.1x%5E2%7D%7B2%7D%20%5D%7C%5Cleft%2060%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
=> ![W= [47(60) - 0.05(60)^2]](https://tex.z-dn.net/?f=W%3D%20%5B47%2860%29%20-%200.05%2860%29%5E2%5D)
=> 