There were 600 students at the north campus and 400 students at the south campus.
<h2 /><h3><u>Calculus</u></h3>
To determine, if 42% of the 1000 students at the east campus are music majors, how many students did the north and south campuses have before the merger, the following calculation must be performed:
- 0.10X + 0.90Y = 420
- 1000 x 0.42 = 420
- 500 x 0.10 + 500 x 0.90 = 50 + 450 = 500
- 600 x 0.10 + 400 x 0.90 = 60 + 360 = 420
Therefore, there were 600 students at the north campus and 400 students at the south campus.
Learn more about calculus in brainly.com/question/6581270
For this case, we have the following equation (according to the comments):

First, we factor the quadratic expression in the denominator:

Then, we multiply both sides of the equation by (a-2) (a + 2):

Later, canceling similar terms we have:

We do distributive property on the left side of the equation:

By grouping variables and constant terms we have:

Rewriting we have:

Finally, by clearing "a" we have:

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.
Answer:
the student correct, but the value of a= -2 is an extraneous solution
Answer:
1/3pi x r^2 / 4 x 2h
Step-by-step explanation:
Ummm I'm just clueless. :/
Answer: x÷(2÷5y)
Step-by-step explanation: this is because you have to first do the quotient of 2 and try then the answer will be divided by 5