Part (i)
I'll use H in place of T to represent the heat of the object. That way there isn't a clash of variables lowercase t vs uppercase T.
The equation we're working with is updated to:
H(t) = 22 + a*2^(bt)
Plugging in t = 0 as the initial time value should lead to the temperature being H = 86 degrees Celsius.
So,
H(t) = 22 + a*2^(bt)
86 = 22 + a*2^(b*0)
86 = 22 + a*2^0
86 = 22 + a*1
86 = 22 + a
a+22 = 86
a = 86-22
a = 64
<h3>Answer: 64</h3>
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Part (ii)
We'll use the value of 'a' we found earlier. Plus we'll use the fact that H = 28 when t = 0.5 (since 30 min = 30/60 = 0.5 hr).
H(t) = 22 + a*2^(bt)
28 = 22 + 64*2^(b*0.5)
28-22 = 64*2^(0.5b)
64*2^(0.5b) = 6
2^6*2^(0.5b) = 6
2^(6+0.5b) = 6
log( 2^(6+0.5b) ) = log(6)
(6+0.5b)*log(2) = log(6)
6+0.5b = log(6)/log(2)
6+0.5b = 2.5849625
0.5b = 2.5849625-6
0.5b = -3.4150375
b = -3.4150375/(0.5)
b = -6.830075
<h3>Answer: Approximately -6.830075</h3>
Answer: 0.790
Step-by-step explanation:
Given : The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level.
The sample size : n= 2004
The number of students read above the eighth grade level = 1584
Then , the proportion of students read above the eighth grade level is given by :-
Hence, the estimate proportion of tenth graders reading at or below the eighth grade level =0.790
Answer:
i think it is a liquid mixture. B
Step-by-step explanation:
somebody pls correct me if im wrong. if my statement isnt wrong i hope this helps
Answer:757m^2
Step-by-step explanation:
A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
8^2 + 5^2 = c^2
64 + 25 = c^2
89 = c^2...take the sqrt of both sides...this eliminates the ^2
sqrt 89 = c
9.4 = c....shortest path is 9.4 km
