Answer:
The water level of the ocean will change
Answer:
45 km/hr
Explanation:
total distance = 90
Increased speed = x+15
90/x - 90/x+15=1/2
90(1/x - 1/x+15)=1/2
90(x+15-x/x^2+15x)=1/2
equation is:
x^2+15x-2700=0
x^2+60x-45x-2700=0
x(x+60)-45(x+60)=0
(x+60)(x-45)=0
x= -60, x=45
reject the negative value = -60
usual speed=45 km/ hr
Answer:
2.84*10^-3 years = 0.00284*10^-3 years
Explanation:
To find the orbital period you use the following formula:

r: 2.0A = 2.0(1.5*10^11m)=3*10^11 m
G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2
M: mass of the sun = 1.98*10^30 kg

Next, you calculate the time in seconds of one Earth's year:

thus, you use this value to find the orbital period of the asteroid in Earth's year:

Answer:
B is the answer to your question
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