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Serga [27]
3 years ago
11

Studying and analyzing others speeches help us to be better:

Social Studies
2 answers:
Dominik [7]3 years ago
7 0
The best and most correct answer among the choices provided by the question is the fourth choice "all of the above." I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions here in Brainly. 
fiasKO [112]3 years ago
5 0

Answer:

D. All of the above

Explanation:

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According to the selection, all of the following are effects of
Dahasolnce [82]

Answer:

The water level of the ocean will change

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3 years ago
B. Solve
Anton [14]

Answer:

45 km/hr

Explanation:

total distance = 90

Increased speed = x+15

90/x - 90/x+15=1/2

90(1/x - 1/x+15)=1/2

90(x+15-x/x^2+15x)=1/2

equation is:

x^2+15x-2700=0

x^2+60x-45x-2700=0

x(x+60)-45(x+60)=0

(x+60)(x-45)=0

x= -60, x=45

reject the negative value = -60

usual speed=45 km/ hr

7 0
3 years ago
Athens can be remembered as one of the first Greek cities to develop what_______​<br>plz help!!!
Ganezh [65]

Answer:

A Democracy

Explanation:

4 0
3 years ago
Read 2 more answers
Suppose that scientists discover an asteroid that is 2.0 AU from the sun. If 1 AU - 150 million km, how long would the asteroid'
Mice21 [21]

Answer:

2.84*10^-3 years = 0.00284*10^-3 years

Explanation:

To find the orbital period you use the following formula:

T=\sqrt{\frac{4\pi^2r^3}{GM}}

r: 2.0A = 2.0(1.5*10^11m)=3*10^11 m

G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2

M: mass of the sun = 1.98*10^30 kg

T=\sqrt{\frac{4\pi^2(3*10^{11}m)^3}{(6.67*10^{-11}Nm^2/kg^2)(1.98*10^{30}kg)}}\\\\T=89839.27\ s

Next, you calculate the time in seconds of one Earth's year:

1\ year=365days*\frac{24\ h}{1\ day}*\frac{3600\ s}{1\ h}=31536000\ s

thus, you use this value to find the orbital period of the asteroid in Earth's year:

T=89839.27\ s*\frac{1\ year}{31536000\ s}=2.84*10^{-3}\ years

5 0
3 years ago
Will mark brainliest
daser333 [38]

Answer:

B is the answer to your question

Please mark brianleist

8 0
3 years ago
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