In math, an isometry is a congruent transformation in which the distance (or length) and the angle is preserved or remains the same even after the transformation.
The transformation can be translation, rotation, reflection, etc.
Let us not use this definition of isometry to answer our question, one at a time.
(I) In here, as we can see the distances 10 and 5 and the angle 43 degrees has been preserved. So, <u>this is an isometry.</u>
(II) In here, distances have been halved, so this is<u> not an isometry</u>, even though the angles have been preserved.
(III) In here, the corresponding distances and the angles have been preserved. So, <u>this is an isometry.</u>
Answer:
$40
Step-by-step explanation:
use y = mx + b
y = amount saved = ?
m = amount saved per week = $10
x = time (in months) saving = 2.5
b = money jerry started with = $15
plug in:
y = (10)(2.5)+15
y = $40
For Y=2x+10 X=y/2 -5. Second x/3
№1. Given: r=8 ft, π≈3.14
C=2×π×r=2×3.14×8=50.24=50.2 ft
A=π×r²=3.14×64=200.96=201 ft²
Answer: 50.2 ft; 201 ft²
№2. Given: D=11 cm, π≈3.14
d=2r or r=2/d, so if d is 11 cm, then r is 11÷2=5.5 cm
C=2×π×r=πD=3.14×11=34.54=34.5 cm
A=π×r²=3.14×(5.5)²=94.985=95 cm²
Answer: 34.5 cm; 95 cm²
The fence is 210 ft long.
There is a post every 3.5 ft.
If you divide 210 ft by 3.5 ft, you get the number of spaces between posts.
(210 ft)/(3.5 ft) = 60
The fence starts with a post. Then there is 3.5 ft of fencing. Then there is another post. Then there is another 3.5 ft of fencing followed by a post. In total there are 61 posts.
Here's another way of thinking of why you end up with 60 posts.
For each 3.5 ft of fencing, you place a post at the end of the fencing.
Since there are 60 3.5-ft-long pieces of fencing, there will be 60 posts, one at the end of each piece of fencing. The first thing that is done is to put the initial post before any fencing is put up. The first post plus 60 more posts add up to 61 posts.
Now that you see why there are 61 posts, we can calculate their cost.
61 * $8.50 = $518.50
